How to find rapidly the coordinates of Q:
since Q is the center of gravity of the triangle ABC, so we have the following vector relationship
vecQA +vecQB +vecQC =<span>vec0
</span><span>vecQA=(x-3, y+2)
</span><span>vecQB=(x-1, y+5)
</span><span>vecQC=(x-7, y+5)
</span><span>vec0=(0, 0)
</span>
so, vecQA +vecQB +vecQC =<span>vec0 is equivalent to
</span>x-3 +x-1+x-7 =0, and y+2+y+5+<span>y+5=0 so 3x-11=0 implies x=11/3
</span><span>and 3y+12=0 implies y=-12/3
finally the </span><span>the coordinates of point Q is (11/3, -4)</span><span>
</span>
Answer:
7p^2 - 3p - 3
Step-by-step explanation:
the simplified version of the expression is 7p^2 - 3p - 3
Answer:
5.3333333333
Step-by-step explanation:
A number is called a rational if it can be written in the form of p/q where p/q are integers and q≠0.
The terminating numbers are always a rational number.
The number 5.3333333... is a rational number.
Hmmmm interesting I really don’t know but
Answer:
i believe its the second part thats wrong
Step-by-step explanation:
1 Distribute
−5(−2+10)=20
10−50=20
2 Add 50 to both sides of the equation
10−50=20
10−50+50=20+50
3 Simplify
Add the numbers
10x−50+50=20+50
10=20+50
Add the numbers
10x =20 + 50
10x=10
4 Divide both sides of the equation by the same term
10x = 70
10x 70
---- = ----
10 10
5 Simplify
Cancel terms that are in both the numerator and denominator
10x 70
---- = ----
10 10
70
x = ----
10
70
x = ----
10
x=7
Solution
= 7
hopes it helps and list brain list plz
