Answer:
The correct option is;
The gas particles move faster, have the same molecular composition, and have weaker attractions between them than the liquid particles
Explanation:
The properties of the gas molecules in comparison to liquids are
1) The gas molecules are widely spread out
2) After evaporation and while in conditions favorable to the gaseous state, the kinetic energy of a gas is larger than the inter molecular attractive forces
3) A gas fills the container in which it is placed
For liquids
1) There are strong intermolecular forces holding the molecules together in a liquid
2) Liquid attractive forces in a liquid are strong enough to hold neighboring molecules
3) The volume of a liquid is definite.
Answer:
q = mC∆T
q = (50 g)(4.184 J/g/deg)(10 deg)
q = 2092 J = 2.09x10^3 J
That's how it's done.
Explanation:
Hope this helps! sorry If i didn't simplify enough..
Answer:
75 inches
Explanation:
A student builds a model of her own bedroom
The scale of the model is 1:25
In the scale model the bed of the student is 3 inches long
Therefore the length of the student's actual bed can be calculated as follows
= 3 × 25
= 75 inches
Hence, the student's actual bed is 75 inches long
Answer:
50 gram calcium do you need
Explanation:
please make me brainlist answer
Answer:
31.9178 °C is the final temperature of the water
Explanation:
![2C_6H_6(l)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(l)+6542 kJ](https://tex.z-dn.net/?f=2C_6H_6%28l%29%2B15O_2%28g%29%5Crightarrow%2012CO_2%28g%29%2B6H_2O%28l%29%2B6542%20kJ)
Mass of benzene burned = 6.200 g
Moles of benzene burned = ![\frac{6.200 g}{78 g/mol}=0.0794 mol](https://tex.z-dn.net/?f=%5Cfrac%7B6.200%20g%7D%7B78%20g%2Fmol%7D%3D0.0794%20mol)
According to reaction , 2 moles of benzene gives 6542 kJ of energy on combustion.
Then 0.0794 mol of benzene on combustion will give:
![\frac{6542 kJ}{2}\times 0.0794 kJ=259.7174 kJ=Q](https://tex.z-dn.net/?f=%5Cfrac%7B6542%20kJ%7D%7B2%7D%5Ctimes%200.0794%20kJ%3D259.7174%20kJ%3DQ)
Mass of water in which Q heat is added = m = 5691 g
Initial temperature = ![T_i=21^oC](https://tex.z-dn.net/?f=T_i%3D21%5EoC)
Final temperature = ![T_f](https://tex.z-dn.net/?f=T_f)
Specific heat of water = c = 4.18 J/g°C
Change in temperature of water = ![T_f-T_i](https://tex.z-dn.net/?f=T_f-T_i)
![Q=mc\Delta t=mc(T_f-T_i)](https://tex.z-dn.net/?f=Q%3Dmc%5CDelta%20t%3Dmc%28T_f-T_i%29)
![259,717.4 J=5691 g\times 4.18 J/g^oC\times (T_f-21^oC)](https://tex.z-dn.net/?f=259%2C717.4%20J%3D5691%20g%5Ctimes%204.18%20J%2Fg%5EoC%5Ctimes%20%28T_f-21%5EoC%29)
![T_f=31.91 ^oC](https://tex.z-dn.net/?f=T_f%3D31.91%20%5EoC)
31.9178 °C is the final temperature of the water