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alexandr1967 [171]
1 year ago
15

Two aircraft rivets, one iron and the other copper, are placed in a calorimeter that has an initial temperature of 20.°C. The da

ta for the rivets are as follows:
Iron Copper
___________________________________
Mass (g) 30.0 20.0
Initial T (°C) 0.0 100.0
c (J/g·K) 0.450 0.387
(a) Will heat flow from Fe to Cu or from Cu to Fe?
Chemistry
1 answer:
Igoryamba1 year ago
8 0

The heat will flow from Cu to Fe because Cu has higher temperature and has lower peak value .

Given ,

two aircraft rivets , one iron and the other copper , are placed in a calorimeter .

the initial temp of the calorimeter is 20 degC .

mass of iron = 30 g

initial temp of iron = 0 degC

Mass of copper = 20 g

initial temp of copper = 100 degC

Here copper has higher temp ,thus heat flow from Cu to Fe .

<h3>What is heat flow ?</h3>

Heat flow is the movement of heat from higher temperature to lower temperature .

<h3>What is calorimeter ?</h3>

It is an object used for measuring the heat flow , heat capacity of a chemical reaction as well as the physical changes .

Learn more about calorimeter here :

brainly.com/question/1407669

#SPJ4

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A scuba diver goes deeper underwater the diver must be aware that the increased pressure affects the human body be increasing th
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Answer:

The amount of dissolved gases in the body. Have a good day! =)

Explanation:

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3 years ago
Can anyone please help me find molar masses of compounds. For example Copper (ll) sulfate (CuSO4)
Alina [70]

Answer:

Explanation:

You would have to add up the atomic masses of all the compounds in the compound, making sure you include how many molecules of each are in the compound

For example, in CuSOA we have 1 molecule of Cu and S, as 4 molecules of O

The atomic masses are as follows:

Cu = 63.55 u

S = 32.065 u

O = 15.99 units

This is how we would add it up:

(Atomic mass of Cu) + (Atomic mass of S) + 4(Atomic Mass of O)

(63.55) + (32.065) + 4(15.99)

(63.55) + (32.065) + 63.96

= 159.575 u

7 0
2 years ago
Read 2 more answers
Consider the following chemical reaction in a small volume of solution. According to LeChatelier’s Principle, which perturbation
stiks02 [169]

Answer:

Decreasing the temperature will shift the equilibrium leftwards towards reactants.

Explanation:

Hello!

In this case, since the reaction between chromate anions and hydrogen ions yields dichromate anions, water and heat, we can infer this is an exothermic reaction by which heat is released (remember in endothermic reactions heat is absorbed as a reactant), it means that considering the LeChatelier’s which states that increasing the temperature of an exothermic reaction shifts the equilibrium leftwards since heat is a product, otherwise (decreasing the temperature) the equilibrium will be shifted rightwards.

Therefore, decreasing the temperature is the perturbation that will shift the equilibrium leftwards towards the reactants.

Best regards!

7 0
2 years ago
Please help y’all I don’t understand
VashaNatasha [74]

Answer:

D.

Explanation:

You try to get 8 electron on the outermost "shell" so you have no left over or "valence" electrons.

6 0
3 years ago
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How many grams of helium must be released to reduce the pressure to 65 atmatm assuming ideal gas behavior? Express the answer in
lyudmila [28]

The question is incomplete, here is the complete question:

How many grams of helium must be released to reduce the pressure to 65 atm assuming ideal gas behavior. Note : 334-mL cylinder for use in chemistry lectures contains 5.209 g of helium at 23°C.

<u>Answer:</u> The mass of helium released is 1.6 grams

<u>Explanation:</u>

We are given:

Mass of helium in the cylinder = 5.209 g

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

Or,

PV=\frac{w}{M}RT

where,

P = Pressure of the gas  = 65 atm

V = Volume of the gas  = 334 mL = 0.334 L   (Conversion factor: 1 L = 1000 mL)

w = Weight of the gas = ?

M = Molar mass of helium gas  = 4 g/mol

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gas = 23^oC=[23+273]K=296K

Putting values in above equation, we get:

65atm\times 0.334L=\frac{w}{4g/mol}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 296K\\\\w=\frac{65\times 0.334\times 4}{0.0821\times 296}=3.573g

Mass of helium released = (5.209 - 3.573) g = 1.636 g = 1.6 g

Hence, the mass of helium released is 1.6 grams

5 0
3 years ago
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