The molar mass of a 0.314-gram sample of gas having a volume of 1.6 l at 287 k and 0.92 atm. is 5.23 gram.
<h3>What is an Ideal Gas ?</h3>
An Ideal Gas is a law for ideal gas which states that the product of Pressure and Volume is equal to the product of the moles of sample, universal gas constant and temperature.
PV = nRT
The given data in the question is
Pressure = 0.92 atm
Volume = 1.6 l
Temperature = 287 K
0.92 * 1.6 = n * 287 * 0.082
n = 0.06 moles
0.06 = 0.314 / molecular weight
molecular weight = 0.314/0.06
Molecular weight = 5.23 gm
Molar mass = 5.23 gm.
The temperature and pressure conditions at which the gas behaves like an ideal gas is 273 K and 1 atm.
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Answer:
P₂ = 0.205torr
Explanation:
Boyle's law relates the pressure and volume of a gas under two different conditions. The equation is:
P₁V₁ = P₂V₂
<em>Where P is pressure and V volume of of 1, initial conditions and 2, final conditions.</em>
P₂ is our incognite
Replacing:
P₁V₁ = P₂V₂
8.20x10⁴torr*15.0L = P₂*600x10⁴L
<h3>P₂ = 0.205torr</h3>
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