Write an equation of the line that passes through (2, -5) and is parallel to the line 2y = 3x + 10

Mathematics

1 answer:

Zarrin [17]3 years ago

8 0

First you get "y" by itself. To do so you divide 2 on both sides.

y = 3/2x + 5

To write an equation of a line that is PARALLEL to this equation, the slopes have to be the SAME. So the slope is 3/2.

You then use the equation:

y = mx + b

SInce you know "m" you plug it in.

y = 3/2x + b

Now you need to find b. To do so you plug in the point (2, -5) into this equation.

-5 = 3/2(2) + b

-5 = 3 + b

-8 = b

Finally you plug in b and you get your new equation.

y = 3/2x - 8

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4 years ago

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3 years ago

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Bas_tet [7]

Answer:

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Step-by-step explanation:

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3 years ago