Answer:
1) 11.581
2) 10.78
3) 14.8
4) 3.5
5) 16.28
6) .64
7) 23.3
8) 1.24
9) 6.53
10) 1.59
11) 8.79
12) 27.7919
Step-by-step explanation:
Ur smarter than u think. ^_^
Answer:
The probability that the first marvel will be red and the second will be green is 7.14%.
Step-by-step explanation:
Since a bag contains 2 red marbles, 2 green marbles and 4 blue marbles, if we choose a marble and then other marble without putting the first one back in the bag, to determine what is the probability that the first marvel will be red and the second will be green, the following calculation must be performed:
2 + 2 + 4 = 8
2/8 x 2/7 = X
0.25 x 0.2857 = X
0.0714 = X
Therefore, the probability that the first marvel will be red and the second will be green is 7.14%.
The answer is 6km
6km is the greatest
I think it's D + .2 = ? i'm not sure but it might be something like that
This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
