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Nimfa-mama [501]

3 years ago

8

A customer comes in with a vehicle that needs tire rotation and wheel alignment. Your bay has a two post frame engaging lift is

it sulked to all of the work that needs to be done? True or False

1 answer:

just olya [345]3 years ago

5 0

Answer:

D

Explanation:

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The link acts as part of the elevator control for a small airplane. If the attached aluminum tube has an inner diameter of 25 mm

aksik [14]

Answer:

Tmax=14.5MPa

Tmin=10.3MPa

Explanation:

T = 600 * 0.15 = 90N.m

$T_max =\frac{T_c}{j} = \frac{x}{y} = \frac{90 \times 0.0175}{\frac{\pi}{2} \times (0.0175^4-0.0125^4)}$

=14.5MPa

$T_{min} =\frac{T_c}{j} = \frac{x}{y} = \frac{90 \times 0.0125}{\frac{\pi}{2} \times (0.0175^4-0.0125^4)}$

=10.3MPa

7 0

3 years ago

Consider a thin suspended hotplate that measures 0.25 m × 0.25 m. The isothermal plate has a mass of 3.75 kg, a specific heat of

Orlov [11]

Answer:

Heat losses by convection, Qconv = 90W

Heat losses by radiation, Qrad = 5.814W

Explanation:

Heat transfer is defined as the transfer of heat from the heat surface to the object that needs to be heated. There are three types which are:

1. Radiation

2. Conduction

3. Convection

Convection is defined as the transfer of heat through the actual movement of the molecules.

Qconv = hA(Temp.final - Temp.surr)

Where h = 6.4KW/m2K

A, area of a square = L2

= (0.25)2

= 0.0625m2

Temp.final = 250°C

Temp.surr = 25°C

Q = 64 * 0.0625 * (250 - 25)

= 90W

Radiation is a heat transfer method that does not rely upon the contact between the initial heat source and the object to be heated, it can be called thermal radiation.

Qrad = E*S*(Temp.final4 - Temp.surr4)

Where E = emissivity of the surface

S = boltzmann constant

= 5.6703 x 10-8 W/m2K4

Qrad = 5.6703 x 10-8 * 0.42 * 0.0625 * ((250)4 - (25)4)

= 5.814 W

7 0

4 years ago

A levee will be constructed to provide some flood protection for a residential area. The residences are willing to accept a one-

777dan777 [17]

Answer:

1709.07 ft^3/s

Explanation:

Annual peak streamflow = Log10(Q [ft^3/s] )

mean = 1.835

standard deviation = 0.65

Probability of levee been overtopped in the next 15 years = 1/5

<u>Determine the design flow ins ft^3/s </u>

P₁₅ = 1 - ( q )^15 = 1 - ( 1 - 1/T )^15 = 0.2

∴ T = 67.72 years

Q₁₅ = 1 - 0.2 = 0.8

Applying Lognormal distribution : Zt = mean + ( K₂ * std ) --- ( 1 )

K₂ = 2.054 + ( 67.72 - 50 ) / ( 100 - 50 ) * ( 2.326 - 2.054 )

= 2.1504

back to equation 1

Zt = 1.835 + ( 2.1504 * 0.65 ) = 3.23276

hence:

Log₁₀ ( Qt(ft^3/s) ) = Zt = 3.23276

hence ; Qt = 10^3.23276

= 1709.07 ft^3/s

4 0

3 years ago

Consider the base plate of an 800-W household iron with a thickness of L = 0.6 cm, base area of A =160 cm2, and thermal conducti

ratelena [41]

Given-

Power, P = 800W

Thickness, L = 0.6cm

Area, A = 160cm²

Thermal conductivity, k = 60W/mK

The heat conduction would be

$\frac{d^2T}{dx^2} + \frac{d^2T}{dy^2} + \frac{d^2T}{dz^2} + \frac{e(gen)}{k} = \frac{1}{\alpha } \frac{dT}{dt}$

Except $\frac{d^2T}{dx^2}$ all the values are 0.

Therefore,

$\frac{d^2T}{dx^2} = 0$

Thus, the boundary conditions here would be

1. $Q_x_=_0 = -kA \frac{dT (0)}{dx} = Q_o$

2. $T(L) = T_L$

4 0

4 years ago

A steel cylindrical sample was subjected to a tensile test. The yield load was 2100N. The maximum load was 3400N and the failure

Misha Larkins [42]

Answer:

initial diameter of the sample is 2.95 mm

Explanation:

given data

yield load = 2100 N

maximum load = 3400 N

failure load = 2350 N

ultimate engineering stress = 497.4 MPa = 497 × $10^{6}$ N/m²

to find out

What was the initial diameter of the sample in mm

solution

we will apply here ultimate engineering stress formula that is express as

ultimate engineering stress = $\frac{Pmax}{A}$ ...............1

here A is area and P max is maximum load applied

so area = $\frac{\pi }{4} d^2$

here d is initial diameter

so put all value in equation 1

497 × $10^{6}$ = $\frac{3400}{\frac{\pi }{4} d^2}$

solve it we get d

d = 2.95 × $10^{-3}$ m

so initial diameter of the sample is 2.95 mm

7 0

4 years ago