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irga5000 [103]
3 years ago
8

A rectangular workpiece has the following original dimensions: 2a=100mm, h=25mm, and width=20mm. The metal has a strengh coeffic

ient of 400MPa and strain-hardening exponent of 0.5. It is being forged in plane strain with mu=0.2. Calculate the force required when the height is reduced by 20 percent. Do not use average pressure formulas.
Engineering
1 answer:
Elena-2011 [213]3 years ago
4 0

Answer:

See attachment for detailed answer.

Explanation:

Download pdf
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Calculate the availability of a system where the mean time between failures is 900 hours and the mean time to repair is 100 hour
Debora [2.8K]

Answer:

The availability of system will be 0.9

Explanation:

We have given mean time of failure = 900 hours

Mean time [to repair = 100 hour

We have to find availability of system

Availability of system is given by  \frac{mean\time\ of\ failure}{mean\ time\ of\ failure+mean\ time\ to\ repair}

So availability of system =\frac{900}{900+100}=\frac{900}{1000}=0.9

So the availability of system will be 0.9

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Showing or hiding records in a database is called “filtering.”<br> True<br> False
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Answer:

TRUE

Explanation:

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2 years ago
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A concrete mix design calls for 6.5 sacks of cement, a water/cement ratio of 0.45, and an air content of 2.5%. 1. Complete the m
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Answer:

28.6 kg

Explanation:

The final weight can be calculated from the mixing data and formulae which is given as follows:

cement content = \frac{water content}{water - cement ratio}

Computing the parameters and checking the tables gives 28.6 kg.

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3 years ago
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A 100 ft long steel wire has a cross-sectional area of 0.0144 in.2. When a force of 270 lb is applied to the wire, its length in
blondinia [14]

Answer:

(a) The stress on the steel wire is 19,000 Psi

(b) The strain on the steel wire is 0.00063

(c) The modulus of elasticity of the steel is 30,000,000 Psi

Explanation:

Given;

length of steel wire, L = 100 ft

cross-sectional area, A = 0.0144 in²

applied force, F = 270 lb

extension of the wire, e = 0.75 in

<u>Part (A)</u> The stress on the steel wire;

δ = F/A

   = 270 / 0.0144

δ  = 18750 lb/in² = 19,000 Psi

<u>Part (B)</u> The strain on the steel wire;

σ = e/ L

L = 100 ft = 1200 in

σ = 0.75 / 1200

σ = 0.00063

<u>Part (C)</u> The modulus of elasticity of the steel

E = δ/σ

   = 19,000 / 0.00063

E = 30,000,000 Psi

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3 years ago
When plotting a single AC cycle beginning at zero degrees and moving forward in time the cycles negative peak occurs at
Lana71 [14]

Answer:A 270 degrees

Explanation:

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