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enot [183]
3 years ago
5

An actual vapour compression system comprises following process represents a. 1-2 Compression process b. 2-3 Condens 1 (or heat

rejection from the condenser) c. 3-4 Irreversible expansion d. 4-1 Evaporation (or) heat addition to the evaporator Sketch the processes on T-S diagram.

Engineering
1 answer:
Gemiola [76]3 years ago
4 0

Answer:

Explanation:

The deatailed diagram of VCRS is given below such

1-2=Isentropic compression in which temperature increases at constant entropy

2-3=Isobaric heat rejection i.e. heat rejected at constant pressure(condensation)

3-4=Irreversible expansion or throttling in which enthalpy remains constant

4-1=Isobaric heat addition(Evaporation)

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tensa zangetsu [6.8K]

Answer

given,

a = 2 t - 10

velocity function

we know,

\dfrac{dv}{dt}=a

\dfrac{dv}{dt}=(2t-10)

integrating both side

\int dv =\int (2t -10) dt

 v = t² - 10 t + C

at t = 0   v = 3

so, 3 = 0 - 0 + C

     C = 3

Velocity function is equal to v = t² - 10 t + 3

Again we know,

\dfrac{dx}{dt}=v

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integrating both side

\int dx =\int (t^2-10t + 3)dt

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now, at t= 0 s = -4

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x = \dfrac{t^3}{3}- 10\dfrac{t^2}{2} + 3 t-4

Position function is equal to x = \dfrac{t^3}{3}- 10\dfrac{t^2}{2} + 3 t-4

8 0
3 years ago
Why a brass lid ring on a glass canning jar will loosen when heated.
Zolol [24]

hi here is your answer hope it helps or then sry

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4 0
3 years ago
A metal rod is 0.600 m in length at a temperature of 15.0∘C. When you raise its temperature to 37.0∘C, its length increases by 0
Katyanochek1 [597]

Answer:

The coefficient of linear expansion of the metal is ∝ = 2.91 x 10⁻⁵  °C⁻¹.

Explanation:

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Given that:

L = 0.6 m

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Δ L = 0.28 mm

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Solution:

We know that Δ T = T₂ ₋ T₁

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Also Δ L = 0.28 mm

Converting the mm to m

Δ L = 0.00028 m

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Rearranging the equation, we get

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Answer:

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