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seropon [69]
2 years ago
5

A cylindrical specimen of this alloy 12 mm in diameter and 188 mm long is to be pulled in tension. Assume a value of 0.34 for Po

isson's ratio.Calculate the stress (in MPa) necessary to cause a 0.0105 mm reduction in diameter.
Engineering
1 answer:
kicyunya [14]2 years ago
8 0

This question is incomplete, the missing image in uploaded along this answer below.

Answer:

The required stress is 200 Mpa

Explanation:

Given the data in the question;

diameter D = 12 mm = 12 × 10⁻³ m

Length L = 188 mm = 188 × 10⁻³ m

Poisson's ratio v = 0.34

Reduction in diameter Δd = 0.0105 mm = 0.0105 × 10⁻³ m

The transverse strain will;

εˣ = Δd / D

εˣ = -0.0105 × 10⁻³ /  12 × 10⁻³ m

εˣ = -0.00088

The longitudinal strain will be;

E^z = - ( εˣ  / v )

E^z = - ( -0.00088  / 0.34 )

E^z = - ( - 0.002588 )

E^z = 0.0026

Now, Using the values for strain, we get the value of stress from the graph provided in the question, ( first image uploaded below.

From the graph, in the Second image;

The stress is 200 Mpa

Therefore, The required stress is 200 Mpa

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Answer:

hello your question is incomplete attached below is the complete question

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3 years ago
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An 80-percent-efficient pump with a power input of 20 hp is pumping water from a lake to a nearby pool at a rate of 1.5 ft3/s th
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Answer:

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solution

we use mechanical pumping power delivered to water is

{W_{u}}= \eta  {W_{pump}}  .............1

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{W_{u}}  = (0.80)(20)

{W_{u}} = 16 hp

and

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\Delta {E_{mech}} = {m} g \Delta z  

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