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2 years ago

What would be the structure for the body points for a persuasive presentation?.

1 answer:

5 0

A persuasive speech is structured like an informative speech. It has an introduction with an attention-getter and a clear thesis statement. It also has a body where the speaker presents their main points and it ends with a conclusion that sums up the main point of the speech.

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A waste stabilization pond is used to treat a dilute municipal wastewater before the liquid is discharged into a river. The infl

german

Answer:

BOD concentration at the outflow = 17.83 mg/L

Explanation:

given data

flow rate of Q = 4,000 m³/day

BOD1 concentration of Cin = 25 mg/L

volume of the pond = 20,000 m³

first-order rate constant equal = 0.25/day

to find out

What is the BOD concentration at the outflow of the pond

solution

first we find the detention time that is

detention time t = $\frac{volume}{flow rate}$

detention time t = $\frac{20000}{4000}$

detention time = 5 days

BOD concentration at the outflow of pond is express as

BOD concentration at the outflow = $Cin ( 1 - e^{-kt} )$

here k is first-order rate constant and t is detention time and Cin is BOD1 concentration

BOD concentration at the outflow = $25 ( 1 - e^{-0.25(5)} )$

BOD concentration at the outflow = 17.83 mg/L

8 0

3 years ago

Implement the function F(A, B, C, D) = Σm(1, 2, 3, 4, 6, 9, 12, 13, 15) as a minimal hazard-free SOP circuit. In your solution,

Marina86 [1]

Answer:

See attachment below

Explanation:

3 0

4 years ago

One - tenth kilogram of air as an ideal gas with k= 1.4 executes a carnot refrigeration cycle as shown i fig. 5,16, the isotherm

maria [59]

Answer:

Hello your question is incomplete attached below is the missing part

a) p1 = 454.83 kPa, p2 = 283.359 Kpa , p3 = 536.423 kpa , p4 = 860.959kPa

b) W12 = 3.4 kJ, W23 = -3.5875 KJ, W34 = -4.0735 KJ, W41 = 3.5875 KJ

c) 5

Explanation:

Given data:

mass of air ( m ) = 1/10 kg

adiabatic index ( k ) = 1.4

temperature for isothermal expansion = 250K

rate of heat transfer ( Q12 ) = 3.4 KJ

temperature for Isothermal compression ( T4 ) = 300k

final volume ( V4 ) = 0.01m ^3

a) Calculate the pressure, in Kpa, at each of the four principal states

from an ideal gas equation

P4V4 = mRT4 ( input values above )

hence P4 = 860.959kPa

attached below is the detailed solution

b) Calculate work done for each processes

attached below is the detailed solution

C) Calculate the coefficient of performance

attached below is detailed solution

6 0

3 years ago

Who want to play "1v1 lol unblocked games 76"

kotegsom [21]

Answer:I want to play what game?

Explanation:

3 0

3 years ago

Read 2 more answers

1. A piston having a diameter of 5.48 inches and a length of 9.50 in slides downward with a velocity, V, through a vertical pipe

const2013 [10]

Answer:

V = 0.00459 ft/s

Explanation:

Since the Piston is moving downwards with a constant velocity V, from the first Newton’s law we know that all vertical forces, must have zero resultant (their sum over vertical axis must equal to zero). Therefore, force that pulls the piston down, is equalized by force of viscous friction Fd= Fvf = 0.5lb (lb here is the pound-force unit). We will relate F ѵ f with τ and from that derive the equation for V.

Fѵf = τ . A

Where τ = µ. du/dy = µ . V/b , and A = π . D . l from this Follows:

Fѵf= (V. A .µ )/b  V= ( Fѵf .b )/(A.µ)

Placing all the known values in the equation ( remember to transform inches to feet, by multiplying inches values with the factor 1/12), we obtain :

ft2

V = ((0.5lb) . (0.002/12 ft))/(π . (5.48/12 ft) . (9.50/12 ft) . (0.016 lb.s/(ft^2 )))

V = 0.00459 ft/s

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3 0

3 years ago