Answer:
3,406.5 litres/hr
Step-by-step explanation:
The liquid is being poured at a rate of 15 gallons per minute.
1 minute = 1/60 hour
Thus, the rate can be written as:
15 gallons pet 1/60 hour
We are told that one gallon is approximately 3.785 liters.
Thus;
15 gallons = 15 × 3.785 litres = 56.775 litres.
Thus, the rate is;
56.775 litres per 1/60 hour
We want to find in litres/hr.
By proportion, we have it as;
(56.775 ÷ 1/60)/1 = 56.775 × 60 = 3,406.5 litres/hr
56km/h is the answer to Question 9
1.5 hours is the answer to Question 10
Leave a comment if you'd like a step-by-step explanation
<span>No It cannot be modeled with a </span>rectangle. <span>A </span>prime<span> polynmial is a </span>polynomial<span> which </span>can<span> only be divided by itself or 1.</span>
Given:
System of linear equations.
Explanation:
System 1:
![\begin{gathered} y\text{ = 3x + 15 } \\ y\text{ = 2x + 11} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20y%5Ctext%7B%20%3D%203x%20%2B%2015%20%7D%20%5C%5C%20y%5Ctext%7B%20%3D%202x%20%2B%2011%7D%20%5Cend%7Bgathered%7D)
The above system of equations can be simplified ELIMINATION BY SUBTRACTION.
System 2:
![\begin{gathered} 7x\text{ - 2y = 0} \\ y\text{ = 6x + 5} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%207x%5Ctext%7B%20-%202y%20%3D%200%7D%20%5C%5C%20y%5Ctext%7B%20%3D%206x%20%2B%205%7D%20%5Cend%7Bgathered%7D)
The above system of equations can be simplified using the SUBSTITUTION METHOD.
System 3:
![\begin{gathered} -3x\text{ - 5y = -5} \\ -3x\text{ + 5y = 5} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20-3x%5Ctext%7B%20-%205y%20%3D%20-5%7D%20%5C%5C%20-3x%5Ctext%7B%20%2B%205y%20%3D%205%7D%20%5Cend%7Bgathered%7D)
The above system of the equation can be simplified using ELIMINATION BY SUBTRACTION.
System 4:
![\begin{gathered} -5x\text{ - 4y = -6} \\ -7x\text{ - 4y = -2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20-5x%5Ctext%7B%20-%204y%20%3D%20-6%7D%20%5C%5C%20-7x%5Ctext%7B%20-%204y%20%3D%20-2%7D%20%5Cend%7Bgathered%7D)
The above system of the equation can be simplified using ELIMINATION BY SUBTRACTION.
System 5:
![\begin{gathered} 5x\text{ + 2y = 0} \\ 15x\text{ + 7y = 0} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%205x%5Ctext%7B%20%2B%202y%20%3D%200%7D%20%5C%5C%2015x%5Ctext%7B%20%2B%207y%20%3D%200%7D%20%5Cend%7Bgathered%7D)
The above system of the equation can be simplified using ELIMINATION BY MULTIPLICATION.
The kinetic energy is 8 J.