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tangare [24]
2 years ago
7

Following a gunshot wound to his head, Jack became more uninhibited, irritable, and profane. It is likely that his personality c

hange was the result of injury to his:
a.parietal lobe.
b.temporal lobe.
c.occipital lobe.
d.frontal lobe.
e.endocrine system.
Physics
1 answer:
Olegator [25]2 years ago
7 0

Answer:

d.Frontal lobe.

Explanation:

Frontal lobe :

This is our brain portion that controls important human mental abilities like the expression of emotion, solving problems, memory, judgment, language, and sexual behavior. Essentially, this is our personality's "control panel" and our ability to interact.

The capacity of a person to make good choices and weigh consequences is often impaired after a frontal lobe injury. Frontal lobe injury can result in increased irritability, which can include a change in attitude and an inability to control behavior.

Total volume of cerebral cortex (human): frontal lobe = 41%; occipital lobe = 18% ; parietal lobe = 19%;temporal lobe = 22%.

Therefore the answer is d.

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Answer:

F = 3.86 x 10⁻⁶ N

Explanation:

First, we will find the distance between the two particles:

r = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2+(z_{2}-z_{1})^2}\\

where,

r = distance between the particles = ?

(x₁, y₁, z₁) = (2, 5, 1)

(x₂, y₂, z₂) = (3, 2, 3)

Therefore,

r = \sqrt{(3-2)^2+(2-5)^2+(3-1)^2}\\r = 3.741\ m\\

Now, we will calculate the magnitude of the force between the charges by using Coulomb's Law:

F = \frac{kq_{1}q_{2}}{r^2}\\

where,

F = magnitude of force = ?

k = Coulomb's Constant = 9 x 10⁹ Nm²/C²

q₁ = magnitude of first charge = 2 x 10⁻⁸ C

q₂ = magnitude of second charge = 3 x 10⁻⁷ C

r = distance between the charges = 3.741 m

Therefore,

F = \frac{(9\ x\ 10^9\ Nm^2/C^2)(2\ x\ 10^{-8}\ C)(3\ x\ 10^{-7}\ C)}{(3.741\ m)^2}\\

<u>F = 3.86 x 10⁻⁶ N</u>

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