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tangare [24]
2 years ago
7

Following a gunshot wound to his head, Jack became more uninhibited, irritable, and profane. It is likely that his personality c

hange was the result of injury to his:
a.parietal lobe.
b.temporal lobe.
c.occipital lobe.
d.frontal lobe.
e.endocrine system.
Physics
1 answer:
Olegator [25]2 years ago
7 0

Answer:

d.Frontal lobe.

Explanation:

Frontal lobe :

This is our brain portion that controls important human mental abilities like the expression of emotion, solving problems, memory, judgment, language, and sexual behavior. Essentially, this is our personality's "control panel" and our ability to interact.

The capacity of a person to make good choices and weigh consequences is often impaired after a frontal lobe injury. Frontal lobe injury can result in increased irritability, which can include a change in attitude and an inability to control behavior.

Total volume of cerebral cortex (human): frontal lobe = 41%; occipital lobe = 18% ; parietal lobe = 19%;temporal lobe = 22%.

Therefore the answer is d.

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3 years ago
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KengaRu [80]

Answer:

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Explanation:

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2 years ago
1) how does reflection differ from diffraction?
Evgesh-ka [11]

Answer: (1) The correct answer is A.

(2) The correct answer is D.

Explanation:

(1)

Reflection is the sending back of light from the surface without absorbing it. In the reflection phenomenon, the wave does not continue moving forward.

Diffraction is the bending of the light around the obstacle. In the diffraction phenomenon, the wave travels forward after striking around the obstacle.

Therefore, the correct answer is A.

(2)

Amplitude is the maximum displacement in the medium from the rest position.

The amount of energy is related to the amplitude. Amplitude is related to the amount of energy carried by the wave. Low energy wave is characterized by a low amplitude. High energy wave is characterized by a high amplitude.

Therefore, the correct option is D.

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3 years ago
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Suppose a police officer is 1/2 mile south of an intersection, driving north towards the intersection at 40 mph. At the same tim
blagie [28]

Answer:

75.36 mph

Explanation:

The distance between the other car and the intersection is,

x=x_{0}+V t \\ x=\frac{1}{2}+V t

The distance between the police car and the intersection is,

y=y_{0}+V t

y=\frac{1}{2}-40 t

(Negative sign indicates that he is moving towards the intersection)

Therefore the distance between them is given by,

z^{2}=x^{2}+y^{2}(\text { Using Phythogorous theorem })

z^{2}=\left(\frac{1}{2}+V t\right)^{2}+\left(\frac{1}{2}-40 t\right)^{2} \ldots \ldots \ldots(1)

The rate of change is,

2 z \frac{d z}{d t}=2\left(\frac{1}{2}+V t\right) V+2\left(\frac{1}{2}-40 t\right)(-40)

2 z \frac{d z}{d t}=V+2 V^{2} t-40+3200 t \ldots \ldots \ldots

Now finding z when t=0, from (1) we have

z^{2}=\left(\frac{1}{2}+V(0)\right)^{2}+\left(\frac{1}{2}-40(0)\right)^{2}

z^{2}=\frac{1}{4}+\frac{1}{4}=\frac{1}{2} \\ z=\sqrt{\frac{1}{2}} \approx 0.7071

The officer's radar gun indicates 25 mph pointed at the other car then, \frac{d z}{d t}=25 when t=0, from

From (2) we get

2(0.7071)(25)=V+2 V^{2}(0)-40+3200(0)

2(0.7071)(25)=V+2 V^{2}(0)-40

35.36=V-40

V=35.36+40=75.36

Hence the speed of the car is 75.36 mph

7 0
3 years ago
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