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3 years ago

Write down all the subsets of {q,r,s}.

Mathematics

1 answer:

MrRissso [65]3 years ago

3 0

{q, r, s} consists of 3 elements, so there are 2³ = 8 possible subsets.

• empty set: { }

• every possible singleton set: {q}, {r}, {s}

• every possible pair: {q, r}, {q, s}, {r, s}

• the set itself: {q, r, s}

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No

Step by step
5/9 5/8 5/7 5/6

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Read 2 more answers

The probability distribution for a

Tpy6a [65]

Answer:

$P(x \le -3) =0.30$

Step-by-step explanation:

Given

The attached probability distribution of x

Required

Find $P(x \le -3)$

To do this, we consider all values of x less than or equal to-3.

So, we have:

$P(x \le -3) =P(x=-5) + P(x = -3)$

From the table:

$P(x=-5) = 0.17$

$P(x = -3) = 0.13$

So, the equation becomes

$P(x \le -3) =P(x=-5) + P(x = -3)$

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$P(x \le -3) =0.30$

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=2x%5E2%2B5x%2B3%3D0" id="TexFormula1" title="2x^2+5x+3=0" alt="2x^2+5x+3=0" align="absmiddle"

melamori03 [73]

Answer:

$x=-\frac{3}{2},-1$

Step-by-step explanation:

$2x^2+5x+3=0$

Split the second term (5x) into two terms. Multiply the coefficient of the first term (2) by the constant term (3):

$2*3=6$

Find which two numbers add up to 5 and multiply into 6:

$3+2=5\\3*2=6\\3,2$

Split 5x as the sum of 3x and 2x:

$2x^2+3x+2x+3$

Now factor out a common term for the first 2 terms:

$2x^2+3x\\x(2x+3)$

And do the same for the last 2 terms:

$2x+3\\1(2x+3)$

Re-insert:

$x(2x+3)+1(2x+3)=0$

Factor out the common term 2x+3 and insert the values in front of the parentheses (x and 1):

$(2x+3)(x+1)=0$

Separate the parentheses and equal them to 0. Solve for x:

$2x+3=0\\2x+3-3=0-3\\2x=-3\\\\\frac{2x}{2}=\frac{-3}{2}\\\\ x=-\frac{3}{2}$

and

$x+1=0\\x+1-1=0-1\\x=-1$

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3 years ago

Houa's family took a road trip to the Grand Canyon. Houa fell asleep 29% of the way

gtnhenbr [62]

Answer:

232 miles had travelled when Houa fell asleep.

Step-by-step explanation:

1. .29 x 800 = 232

7 0

3 years ago