Answer:
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Explanation:
A poem about the scientific method
Identify the common substance that has the highest
1 answer:
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156251.099 grams of O₂ are required to burn 17.0 gal of C₈H₁₈
<h3>Further explanation</h3>Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of mass
The unit of density can be expressed in g / cm³ or kg / m³
Density formula:
ρ = density
m = mass
v = volume
1 gal equal to = 3785.41 ml
then 17.0 gal = 17 x 3785.41 = 64351.97 ml Octane
grams Octane = ρ x ml
grams Octane = 0.692 g.ml x 64351.97
grams Octane = 44531.563
molar mass Octane (C₈H₁₈) = 114
mole Octane = grams : molar mass
mole Octane = 44531.563 : 114
mole Octane = 390.627
From the reaction
C₈H₁₈ + 25/2 O₂ ⇒ 8 CO₂ + 9H₂O
mole C₈H₁₈ : mole O₂ = 1 : 25/2
mole O₂ = 4882.846
grams O₂ = mole x molar mass
grams O₂ = 4882.846 x 32
grams O₂ = 156251.099
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Keywords: Octane, mole, mass, gal, density
Answer: The mass of the gas is 18.3 g/mol.
Explanation:
To calculate the rate of diffusion of gas, we use Graham's Law.
This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:
Squaring both sides and solving for
Hence, the molar mas of unknown gas is 18.3 g/mol.