Standard reduction potentials are based on which element?
1 answer:
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This is an incomplete question, here is a complete question.
Calculate the solubility of each of the following compounds in moles per liter. Ignore any acid-base properties.
CaCO₃, Ksp = 8.7 × 10⁻⁹
Answer : The solubility of CaCO₃ is,
Explanation :
As we know that CaCO₃ dissociates to give ion and
ion.
The solubility equilibrium reaction will be:
The expression for solubility constant for this reaction will be,
Let solubility of CaCO₃ be, 's'
Therefore, the solubility of CaCO₃ is,
Answer:
Explanation:
The amount adsorbed (solute) is the acetic acid, and the adsorbent is the activated charcoal. The mass of the adsorbent is 10 g.
So, we need to calculate the mass of the acetic acid as follows:
Where:
n: is the number of moles = C*V
M: is the molecular mass = 60.052 g/mol
C: is the final concentration of the acid = 0.5*0.2 mol/L = 0.10 mol/L
V: is the volume = 50 ml = 0.050 L
Now, the amount of solute adsorbed per gram of the adsorbent is:
Therefore, the amount of solute adsorbed per gram of the adsorbent is 0.03 g/g.
I hope it helps you!