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myrzilka [38]
3 years ago
14

In which state do the particles have the most energy?

Chemistry
2 answers:
HACTEHA [7]3 years ago
5 0

Answer:

gas

Explanation:

Furkat [3]3 years ago
3 0
The gas state.

Because they are not confined by a certain place. All the molecules are bouncing off eachother.
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A sample of methane at a pressure of 1.00 atm and a temperature of 93.1 K is heated at constant pressure to a temperature of 158
Zinaida [17]

Answer:

b. The final state of the substance is a gas.

d. The sample is initially a liquid. One or more phase changes will occur.

Explanation:

Methane has the following properties:

  • Normal melting point: 90.7 K
  • Normal boiling point: 111.65 K

*"Normal" refers to normal pressure (1 atm).

According to this, we can affirm:

  • Below 90.7 K, methane is solid.
  • Between 90.7 K and 111.65 K, methane is liquid.
  • Above 111.65 K, methane is gas.

<em>A sample of methane at a pressure of 1.00 atm and a temperature of 93.1 K is heated at constant pressure to a temperature of 158 K. Which of the following are true? Choose all that apply.</em>

<em>a. The liquid initially present will solidify.</em>  FALSE. The liquid will vaporize.

<em>b. The final state of the substance is a gas.</em>  TRUE.

<em>c. The sample is initially a solid.</em>  FALSE. The sample is initially a liquid.

<em>d. The sample is initially a liquid. One or more phase changes will occur. </em>TRUE.

4 0
2 years ago
18. How many moles of atoms are there in each of
Lelechka [254]

a) 1 mole of Ne

b) i/2 mole of Mg

c) 1570 moles of Pb.

d) 2.18125*10^-13 moles of oxygen.

                     

Explanation:

The number of moles calculated by Avogadro's number in 6.23*10^23 of Neon.

6.23*10^23= 1/ 6.23*10^23

                   = 1 mole

The number of moles calculated by Avogadro's number in 3.01*10^23 of  Mg

3.2*10^23=1/6.23*10^23

                = 1/2 moles of Pb.

Number of moles in 3.25*10^5 gm of lead.

atomic weight of Pb=

n=weight/atomic weight

  = 3.25*10^5/ 207

  = 1570 moles of Pb.

Number of moles 4.50 x 10-12 g O

number of moles= 4.50*10^-12/16

                            =  2.18125*10^-13 moles of oxygen.

3 0
3 years ago
if one mole of calcium carbonate (the limiting reactant) is used, how much calcium chloride should the reaction produce? look at
salantis [7]

Answer:

The answer to your question is <u>111 g of CaCl₂</u>

Explanation:

Reaction

                 2HCl  +  CaCO₃   ⇒    CaCl₂  +  CO₂  +  H₂O

Process

1.- Calculate the molecular mass of Calcium carbonate and calcium chloride

CaCO₃ = (1 x 40) + (1 x 12) + ((16 x 3) = 100 g

CaCl₂ = (1 x 40) + (35.5 x 2) = 111 g

2.- Calculate the amount of calcium chloride produced using proportions.

The proportion CaCO₃ to CaCl₂ is   1 : 1.

                      100 g of CaCO₃  ------------- 111 g of CaCl₂

Then 111g of CaCl₂ will be produced.

5 0
3 years ago
Between HClO3 and HIO3, which is stronger and why? Question 16 options: 1) HClO3 is stronger because chlorine is in a higher oxi
natima [27]

Answer:

2) HClO3 is stronger because chlorine is more electronegative than iodine.

Explanation:

The more electronegative the element is the more strong or acidic it becomes.

Chlorine being more electronegative than Iodine makes it easier for it to pull the electron of hydrogen more strongly and hence has a higher tendency to release a H+ unit. Hence that makes it stronger.

4 0
3 years ago
How can helium exist in three different forms
saul85 [17]

Explanation:

Helium exists in three different forms due to the phenomenon of isotopy. Isotopy is the existence of two or more atoms of the same element having the same atomic number but different mass numbers due to the differences in the number of neutrons in their nuclei.

  • The atoms of these elements are called isotopes.
  • This is why Helium can exist in three different forms.
  • Isotopes have the same electronic configuration but with the same chemical properties.

Learn more:

isotopes brainly.com/question/1915462

Isotopy brainly.com/question/2593342

#learnwithBrainly

6 0
3 years ago
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