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3 years ago

2 Equation on chemistry that I have been struggling with, needed some assistance

Chemistry

1 answer:

crimeas [40]3 years ago

7 0

Answer:

2. Copper (II) carbonate plus sulfuric acid produces copper (II) sulfate and carbon dioxide and water.

We need the "II" after copper to specify what charge it is. It's +2 because carbonate is -2.

3. Calcium hydroxide plus carbon dioxide gas produces calcium carbonate and water.

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Can someone please help me with this question??

dsp73

I think the answer is b

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3 years ago

Dl water will test _________for protein?

Ann [662]

Answer:

Total protein range. The normal range for total protein is between 6 and 8.3 grams per deciliter (g/dL). This range may vary slightly among laboratories.

Explanation:

5 0

3 years ago

2. 2. Consider the following reaction occurring in a closed chemical system. Assume that this reaction is at equilibrium and tha

Alika [10]

1. This is a combustion reaction.

Combustion reactions can happen with the presence of O₂ gas. O₂ reacts with another element or compound and oxidize it. Here ethanol reacts with O₂ and produces CO₂ and H₂O as products. Combustion is also called as burning. 

2. Reaction will shift to right. 

If more CH₃CH₂OH is added to the system, then the amount of CH₃CH₂OH will increase. Then the equilibrium in the system will be broken. To make the equilibrium again, the added CH₃CH₂OH should be removed. To do that system will consume more CH₃CH₂OH to make products which helps to decrease the amount of ethanol. Hence, the reaction will shift to right.

3. The reaction will shift to right.

If the water is extracted from the system, the amount of water will decrease. That means the amount of products decrease. Then the system will try to gain equilibrium by increasing the water. To increase water the forward reaction should be enhanced. Hence, the reaction will shift to right.

4. The reaction will shift to right.

This is an exothermic reaction since it produces heat. If the produced heat is removed, then the system will be cold. To maintain the temperature, system has to increase the amount of heat produced. Then, the forward reaction should be enhanced. Hence, the reaction will shift to right.

5. The Le Chatelier's principle.

Le Chatelier's principle says if a condition changes in a system which was in an equilibrium state, the system will try to gain equilibrium by correcting the changed condition back to normal. Most of industries which make chemicals use this principle

3 0

3 years ago

Read 2 more answers

1.) The process for converting ammonia to nitric acid involves the conversion of NH3 to

Firdavs [7]

Answer:

a) 1.39 g ; b) O₂ is limiting reactant, NH₃ is excess reactant; c) 0.7 g

Explanation:

We have the masses of two reactants, so this is a limiting reactant problem.

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.

MM: 17.03 32.00 30.01

4NH₃ + 5O₂ ⟶ 4NO + 6H₂O

Mass/g: 1.5 1.85

2. Calculate the moles of each reactant

$\text{moles of NH}_{3} = \text{1.5 g NH}_{3} \times \dfrac{\text{1 mol NH}_{3}}{\text{17.03 g NH}_{3}} = \text{0.0881 mol NH}_{3}\\\\\text{moles of O}_{2} = \text{1.85 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.057 81 mol O}_{2}$

3. Calculate the moles of NO we can obtain from each reactant

From NH₃:

The molar ratio is 4 mol NO:4 mol NH₃

$\text{Moles of NO} = \text{0.0881 mol NH}_{3} \times \dfrac{\text{4 mol NO}}{\text{4 mol NH}_{3}} = \text{0.0881 mol NO}$

From O₂:

The molar ratio is 4 mol NO:5 mol O₂

$\text{Moles of NO} = \text{0.057 81 mol O}_{2}\times \dfrac{\text{4 mol NO}}{\text{5 mol O}_{2}} = \text{0.046 25 mol NO}$

4. Identify the limiting and excess reactants

The limiting reactant is O₂ because it gives the smaller amount of NO.

The excess reactant is NH₃.

5. Calculate the mass of NO formed

$\text{Mass of NO} = \text{0.046 25 mol NO}\times \dfrac{\text{30.01 g NO}}{\text{1 mol NO}} = \textbf{1.39 g NO}$

6. Calculate the moles of NH₃ reacted

The molar ratio is 4 mol NH₃:5 mol O₂

$\text{Moles reacted} = \text{0.057 81 mol O}_{2} \times \dfrac{\text{4 mol NH}_{3}}{\text{5 mol O}_{2}} = \text{0.046 25 mol NH}_{3}$

7. Calculate the mass of NH₃ reacted

$\text{Mass reacted} = \text{0.046 25 mol NH}_{3} \times \dfrac{\text{17.03 g NH}_{3}}{\text{1 mol NH}_{3}} = \text{0.7876 g NH}_{3}$

8. Calculate the mass of NH₃ remaining

Mass remaining = original mass – mass reacted = (1.5 - 0.7876) g = 0.7 g NH₃

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2 years ago

Yo what is the moon phases

Fynjy0 [20]

Answer:

New Moon, First Quarter, Full Moon, Last Quarter, Waxing Crescent, Waxing Gibbous, Waning Gibbous, and Waning Crescent.

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2 years ago

Read 2 more answers