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Lady bird [3.3K]
3 years ago
7

Identify the state of matter for A, B, and C.

Chemistry
1 answer:
drek231 [11]3 years ago
7 0

Explanation:

A) particles are close together in random positions with about equal kinetic energy and intermolecular forces.

These points are about liquid state.

B) particles are close together in fixed positions with low kinetic energy

These points satisfy the qualities of Solid state

C)particles are far apart with greater kinetic energy and low intermolecular forces.

The above qualities are for Gaseous state of matter

A) Liquid

B)Solid

C)Gas

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Which of the following molecules has the same empirical formula as glucose (C6H1206)
timama [110]

Answer:

ethanoic acid

Explanation:

as it also contains carbon dioxide water and oxygen as glucose

hope it helps you

please mark me as brainlist

4 0
3 years ago
Read 2 more answers
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Supposed 0.301 g of methane
Nina [5.8K]

Answer:

The maximum mass of CO2 that could be produced is 0.1925 grams

Explanation:

Step 1: Data given

Mass of methane = 0.301 grams

Mass of oxygen = 0.28 grams

Molar mass of ethane = 16.04 g/mol

Molar mass of oxygen = 32 g/mol

Step 2: The balanced equation

CH4 + 2O2 → CO2 + 2H2O

For 1 mole methane consumed, we need 2 moles of O2 to produce 1 mole of CO2 and 2 moles of H2O

Step 3: Calculate moles of methane

Number of moles =Mass / Molar mass

Number of moles CH4 = 0.301 grams /16.04 g/mol

Moles CH4 = 0.0188 moles

Step 4: Calculate moles oxygen

Number of moles oxygen = 0.28 grams / 32 g/mol

Moles oxygen = 0.00875 moles

Step 5: the limiting reactant

For 1 mole methane consumed, we need 2 moles of O2

Oxygen is the limiting reactant. It will be completely consumed.

Methane is in excess. There will be consumed 0.00875 /2  = 0.004375 moles

There will remain 0.0188 - 0.004375 = 0.014425 moles

Step 6: Calculate moles of CO2

For 1 mole methane consumed, we need 2 moles of O2 to produce 1 mole of CO2

For 0.00875 moles oxygen , we have 0.004375 moles CO2

Step 7: Calculate mass of CO2

Mass CO2 = moles CO2 * Molar mass CO2

Mass CO2 =0.004375 * 44.01 g/mol = 0.1925 grams CO2

The maximum mass of CO2 that could be produced is 0.1925 grams

8 0
3 years ago
Which compounds can be made with the reaction benzene via electrophilic aromatic substitution using isopropyl chloride and AlCl3
Hitman42 [59]

Answer:

isopropyl benzene (cumene)

Explanation:

The reaction of isopropyl chloride and AlCl3 and benzene belongs to the class of organic reactions known as the Friedel Kraft alkylation.

The mechanism of the reaction involves the formation of a tetrahedral complex [AlCl4]^-.

The electrophile now is the isopropyl group which attacks the benzene to yield the product.

4 0
3 years ago
2H2 + O2 --&gt; 2 H2O<br> +<br> How many moles of oxygen is required to produce 13.3 moles of water?
LenKa [72]

Answer:

Explanation:

Let the number of moles of oxygen = x

2H2 + O2 --> 2 H2O

           x             13.3

Since the balance number for oxygen is 1 and the balance number for water is 2, you must set up a proportion. (Those balance numbers represent the number of moles).

1/x = 2 / 13.3                      Cross Multiply

2*x = 13.3                          Divide both sides by 2

2x/2 = 13.3/2

x = 6.65

You need 6.65 moles of oxygen.

8 0
2 years ago
27. The density of nickel is 8.91 g/cm3. How large a cube, in cm3, would contain 2.00 x 10^24 atoms of nickel? Use dimensional a
jok3333 [9.3K]

Answer : The volume of the cube is, 21.88cm^3

Solution : Given,

Density of nickel = 8.91g/cm^3

Number of nickel atoms = 2\times 10^{24}

Molar mass of nickel = 58.7 g/mole

First we have to calculate the moles of nickel.

As, 6.022\times 10^{23} atoms form 1 mole of nickel

So, 2\times 10^{24} atoms form \frac{2\times 10^{24}}{6.022\times 10^{23}}=3.321 moles of nickel

The moles of nickel = 3.321 moles

Now we have to calculate the mass of nickel.

\text{ Mass of Ni}=\text{ Moles of Ni}\times \text{ Molar mass of Ni}

\text{ Mass of Ni}=(3.321moles)\times (58.7g/mole)=194.94g

The mass of nickel = 194.94 g

Now we have to calculate the volume of nickel.

Density=\frac{Mass}{Volume}

8.91g/cm^3=\frac{194.94g}{Volume}

Volume=21.88cm^3

Therefore, the volume of the cube is, 21.88cm^3

4 0
3 years ago
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