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S_A_V [24]
4 years ago
6

Potassium (K) and calcium fluoride (CaF2) can both be classified as (Please help)

Chemistry
1 answer:
nasty-shy [4]4 years ago
8 0
Potassium and calcium fluoride are both metals
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Question 54
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What type of reactive intermediate is formed upon irradiation of a solution of toluene (ph-ch3) and bromine?
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<span>Answer: Benzylic radical . First Br radicals are produced which strip off a H- from the methyl group. The benzylic radical the reacts with Br2 to form benzylic bromide and another Br radical.</span>
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Endoplasmic reticulum is found in the cells of
vovangra [49]

Endoplasmic reticulum is an organelle found in both eukaryotic animal and plant cells.

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3 years ago
Read 2 more answers
2H2 + O2 --&gt; 2H2OHow many moles of hydrogen gas are needed to produce 120g of water?
wlad13 [49]
<h2>Answer:</h2>

6.67moles

<h2>Explanations:</h2>

Given the balanced chemical reaction between hydrogen and oxygen expressed as:

2H_2+O_2\rightarrow2H_2O

First, you need to calculate the moles of water produced.

\begin{gathered} \text{Moles}=\frac{Mass}{\text{Molar mass}} \\ \text{Moles of water=}\frac{120}{2(1)+16} \\ \text{Moles of water}=\frac{120}{18} \\ \text{Moles of water}=6.67\text{moles} \end{gathered}

Based on stochiometry, 2 moles of hydrogen produces 2 moles of water, hence the moles of hydrogen that will be needed to produce 120g of water is 6.67moles

6 0
1 year ago
A chemist has one solution that is 20% salt and a second solution that is 45% salt. How many liters of each should be used in or
Free_Kalibri [48]

Answer:

8 liters of the first salt solution and 12 liters of the second salt solution is needed to get 20L of a solution that is 30% salt

Explanation:

Let x represent the liters of the first salt solution

Let y represent the liters of the second salt solution

x + y= 20......equation 1

x= 20-y

The first solution is 20% salt and the second solution is 45% salt

20/100x + 45/100 y= 30/100 × 20

0.2x + 0.45y= 0.3×20

0.2x + 0.45y= 6............equation 2

Substitute 20-y for x in equation 2

0.2(20-y) + 0.45y= 6

4-0.2y+ 0.45y= 6

4 + 0.25y= 6

0.25y= 6-4

0.25y= 2

y= 2/0.25

y= 8

Substitute y for 8 in equation 1

x + y= 20

x + 8=20

x= 20-8

x= 12

Hence 8 liters of the first salt solution and 12 liters of the second salt solution is needed to get 20L of a solution that is 30% salt.

4 0
3 years ago
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