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3 years ago

Someone pls help me with this.

Mathematics

2 answers:

Assoli18 [71]3 years ago

4 0

Answer: m∠D = 65°

Step-by-step explanation:

The best solve method for problems like this is say the sum of the angle values equals 360.

2x-15+2x-15+x+x = 360

Then from here you just simplify.

4x+2x-30 = 360

6x = 390

x = 65

So the measure of Angle D equals 65 degrees.

Zigmanuir [339]3 years ago

3 0

We know, sum of all angles of a quadrilateral is 360°.

Therefore, angle A + angle B + angle C + angle D = 360°

or, (2x-15)+x+(2x-15)+x = 360

or, 6x-30 = 360

or, 6x = 360+30

or, 6x = 390

or, x = 390/6 = 65

Therefore, measure of angle D = x° = 65°

The answer is option d. 65°

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Suppose you send about 12 text messages a day, and your older sister sends more text messages than you do. Together, you send a

frozen [14]

Answer: so your sister sends 14 messages a day

Step-by-step explanation: you send about twelve texts a day and as a total you both send 26 so lets let your sister be x and you are 12

26- 12=x

26-12= 14

I hope this was helpful!

3 0

2 years ago

Please help and i have many more points!

Slav-nsk [51]

Answer:

its A im pretty sure

Step-by-step explanation:

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2 years ago

The equation is 2(4x-11)=10 and how do you divide each side of the equation by 2.

Ierofanga [76]

Answer:

4x-11=5

Step-by-step explanation:

If u were to divide each side of the equation by 2, the 2 on the left which is supposed to distribute into the parenthesis would disappear, and the 10 on the right side would turn into 5.

What is left is this,

4x-11=5

7 0

3 years ago

AB lies on a number line. The coordinate of point A is -6. Given that AB=20, what are two possible coordinates for point B?

Dafna1 [17]

Answer:

Step-by-step explanation:

Given that

Coordinate of point A is -6.

Length of AB = 20

To find:

Coordinates for the point B = ?

Solution:

We are given that:

AB = 20

In other words, we can use modulus function to define the distance between A and B:

|Coordinates of B - Coordinates of A| = 20

Let the coordinates of B = $x$

Kindly refer to the attached image for the given situation.

Point B might be either on the left or on the right side of A.

That means:

$|x-(-6)| = 20\\\Rightarrow |x+6|=20$

Now, let us have a look at the modulus function:

$|y|=\left \{ {-{y}\ if\ y0} \right.$

So,

$|x+6|=\left \{ {-{(x+6)}\ if\ (x+6)0} \right.$

$(x+6 ) =20\\\Rightarrow x =14$

$-(x+6 ) =20\\\Rightarrow x =-26$

Therefore, the answer is:

4 0

3 years ago

Tacoma's population in 2000 was about 200 thousand, and had been growing by about 9% each year. a. Write a recursive formula for

KIM [24]

Answer:

a) The recurrence formula is $P_n = \frac{109}{100}P_{n-1}$ .

b) The general formula for the population of Tacoma is

$P_n = \left(\frac{109}{100}\right)^nP_{0}$ .

c) In 2016 the approximate population of Tacoma will be 794062 people.

d) The population of Tacoma should exceed the 400000 people by the year 2009.

Step-by-step explanation:

a) We have the population in the year 2000, which is 200 000 people. Let us write $P_0 = 200 000$ . For the population in 2001 we will use $P_1$ , for the population in 2002 we will use $P_2$ , and so on.

In the following year, 2001, the population grow 9% with respect to the previous year. This means that $P_0$ is equal to $P_1$ plus 9% of the population of 2000. Notice that this can be written as

$P_1 = P_0 + (9/100)*P_0 = \left(1-\frac{9}{100}\right)P_0 = \frac{109}{100}P_0$ .

In 2002, we will have the population of 2001, $P_1$ , plus the 9% of $P_1$ . This is

$P_2 = P_1 + (9/100)*P_1 = \left(1-\frac{9}{100}\right)P_1 = \frac{109}{100}P_1$ .

So, it is not difficult to notice that the general recurrence is

$P_n = \frac{109}{100}P_{n-1}$ .

b) In the previous formula we only need to substitute the expression for $P_{n-1}$ :

$P_{n-1} = \frac{109}{100}P_{n-2}$ .

Then,

$P_n = \left(\frac{109}{100}\right)^2P_{n-2}$ .

Repeating the procedure for $P_{n-3}$ we get

$P_n = \left(\frac{109}{100}\right)^3P_{n-3}$ .

But we can do the same operation n times, so

$P_n = \left(\frac{109}{100}\right)^nP_{0}$ .

c) Recall the notation we have used:

$P_{0}$ for 2000, $P_{1}$ for 2001, $P_{2}$ for 2002, and so on. Then, 2016 is $P_{16}$ . So, in order to obtain the approximate population of Tacoma in 2016 is