We know that the electron clouds of two atoms overlapping is a bond, because that signifies that the electrons are being shared in a bond.
So, I'm going to go through some definitions of these different types of bonds, because they have very specific circumstances.
<u>A hydrogen bond is a bond between an electronegative atom and a hydrogen molecule</u> (which is not what this question says, this isn't stated anywhere).
<u>A dipole is a difference in electron density on two different atoms</u> (so this isn't even close to what the question is stating, a dipole is not even a bond)
<u>An ionic bond is an </u><u><em>unequal sharing of electrons</em></u><u> between two atoms </u>(because the question doesn't state this specific fact, then it can't be this option).
By process of elimination, we know the answer is covalent bond, but just in case, we can also look at the definition of a covalent bond: <u>a bond that involves the sharing of electrons between atoms.</u>
That is exactly what the question is asking for! Therefore, your answer is d. covalent bond
Answer: 14.3%Explanation: In order to find the mass percent of hydrogen in this compound, you must determine how many grams of hydrogen you'd get in 100 g of compound.
In your case, you know that an unknown mass of hydrogen reacts with 0.771 g of carbon to form 0.90 g of hydrocarbon, which is a compound that contains only carbon and hydrogen.
Use the total mass of the hydrocarbon to determine how many grams of hydrogen reacted with the carbon.
Now, if 0.90 g of this compound contain 0.129 g of hydrogen, it follows that 100 g of this compound will contain.
So, if 100 g of this compound contain 14.33 g of hydrogen, it follows that the mass percent of hydrogen is 14.3%
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Answer: electrons
Explanation: A chemical bond is when there is a transfer (movement) of electrons from one atom to another.
Answer:
b. Add a few drops of one of the layers to a test tube containing 1 mL of water. Shake the test tube to determine the solubility of the layer in water
Explanation:
Option a is not true, it depends on the compound being extracted.
Option c is not true, although most of the solvents used in extractions have lower boiling point than water there are exceptions, for example toluene.
Option d is not true. Again most of the solvents used in extractions are less dense than water, there are many exceptions, for example chloroform, so for equal volumes the chloroform layer will weigh more.
Option b. is the correct one.
One will test the miscibility of the layer in water. If it inmiscible then one would know is the organic layer. If it is the aqueous layer then it will completely be miscible.
