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SpyIntel [72]
1 year ago
10

A speedboat with a mass of 531 kg (including the driver) is tethered to a fixed buoy by a strong 30.3 m cable. The boat's owner

loves high speed, but does not really want to go anywhere. So the owner revs up the boat's engine, makes a lot of noise, and runs the boat in circles around the buoy with the cable supplying all the necessary centripetal force. When the tension of the cable is steady at 12900 N, with what force is the boat's engine pushing the boat? Different physics textbooks treat drag force somewhat differently and use different formulas. For the present purpose, take the water's drag force on the boat to be (450 kg/m)×2, where denotes the boat's speed. Ignore any drag force on the cable.
Physics
1 answer:
zaharov [31]1 year ago
4 0

As the tension in the rope is constant therefore the boat engine will also be pushing the boat with the same force as that of the drag force that is given to be 450 Newton.

<h3>What is a drag force?</h3>

Drag force is similar to friction force but is experienced by a moving body in a fluid. Direction of drag force is a positive to the direction of motion.

<h3>What is centripetal force?</h3>

Centripetal force is not a new force in nature but a manifestation of some force that causes rotation of a body.

Given:

Mass of the boat = 531 kg

Tension in the cable = 12900 Newton

Drag force experienced by the boat = 450 N

The boat along with the man is rotating using a cable which experiences a constant tension of 12900 Newton.

The boat's engine should also be generating a force perpendicular to the circular path travelled by the boat.

Now the tension in the string is constant this implies that all the force that the both engine is generating is being used in balancing the drag force exerted by water on the boat.

Therefore, the force produced by the engine will be equal to 450 Newton which will be used to balance the drag force.

Learn more about drag force here: brainly.com/question/27817330

#SPJ1

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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

According to above question ~

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Let's find the charge (q) by using formula ~

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