1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SpyIntel [72]
11 months ago
10

A speedboat with a mass of 531 kg (including the driver) is tethered to a fixed buoy by a strong 30.3 m cable. The boat's owner

loves high speed, but does not really want to go anywhere. So the owner revs up the boat's engine, makes a lot of noise, and runs the boat in circles around the buoy with the cable supplying all the necessary centripetal force. When the tension of the cable is steady at 12900 N, with what force is the boat's engine pushing the boat? Different physics textbooks treat drag force somewhat differently and use different formulas. For the present purpose, take the water's drag force on the boat to be (450 kg/m)×2, where denotes the boat's speed. Ignore any drag force on the cable.
Physics
1 answer:
zaharov [31]11 months ago
4 0

As the tension in the rope is constant therefore the boat engine will also be pushing the boat with the same force as that of the drag force that is given to be 450 Newton.

<h3>What is a drag force?</h3>

Drag force is similar to friction force but is experienced by a moving body in a fluid. Direction of drag force is a positive to the direction of motion.

<h3>What is centripetal force?</h3>

Centripetal force is not a new force in nature but a manifestation of some force that causes rotation of a body.

Given:

Mass of the boat = 531 kg

Tension in the cable = 12900 Newton

Drag force experienced by the boat = 450 N

The boat along with the man is rotating using a cable which experiences a constant tension of 12900 Newton.

The boat's engine should also be generating a force perpendicular to the circular path travelled by the boat.

Now the tension in the string is constant this implies that all the force that the both engine is generating is being used in balancing the drag force exerted by water on the boat.

Therefore, the force produced by the engine will be equal to 450 Newton which will be used to balance the drag force.

Learn more about drag force here: brainly.com/question/27817330

#SPJ1

You might be interested in
A group of students prepare for a robotic competition and build a robot that can launch large spheres of mass M in the horizonta
jeyben [28]

Answer:

V_0

Explanation:

Given that, the range covered by the sphere, M, when released by the robot from the height, H, with the horizontal speed V_0 is D as shown in the figure.

The initial velocity in the vertical direction is 0.

Let g be the acceleration due to gravity, which always acts vertically downwards, so, it will not change the horizontal direction of the speed, i.e. V_0 will remain constant throughout the projectile motion.

So, if the time of flight is t, then

D=V_0t\; \cdots (i)

Now, from the equation of motion

s=ut+\frac 1 2 at^2\;\cdots (ii)

Where s is the displacement is the direction of force, u is the initial velocity, a is the constant acceleration and t is time.

Here, s= -H, u=0, and a=-g (negative sign is for taking the sigh convention positive in +y direction as shown in the figure.)

So, from equation (ii),

-H=0\times t +\frac 1 2 (-g)t^2

\Rightarrow H=\frac 1 2 gt^2

\Rightarrow t=\sqrt {\frac {2H}{g}}\;\cdots (iii)

Similarly, for the launched height 2H, the new time of flight, t', is

t'=\sqrt {\frac {4H}{g}}

From equation (iii), we have

\Rightarrow t'=\sqrt 2 t\;\cdots (iv)

Now, the spheres may be launched at speed V_0 or 2V_0.

Let, the distance covered in the x-direction be D_1 for V_0 and D_2 for 2V_0, we have

D_1=V_0t'

D_1=V_0\times \sqrt 2 t [from equation (iv)]

\Rightarrow D_1=\sqrt 2 D [from equation (i)]

\Rightarrow D_1=1.41 D (approximately)

This is in the 3 points range as given in the figure.

Similarly, D_2=2V_0t'

D_2=2V_0\times \sqrt 2 t [from equation (iv)]

\Rightarrow D_2=2\sqrt 2 D [from equation (i)]

\Rightarrow D_2=2.82 D (approximately)

This is out of range, so there is no point for 2V_0.

Hence, students must choose the speed V_0 to launch the sphere to get the maximum number of points.

7 0
3 years ago
Anthony walks to the pizza place for lunch. He walk 1km east, then 1km south and then 1km east again. What distance did he cover
Komok [63]

Answer:

Pizza pizzza pizza

Explanation:

little ceasrs

8 0
2 years ago
A fisherman is fishing from a bridge and is using a "44.0-N test line." In other words, the line will sustain a maximum force of
vitfil [10]

Answer:

a) 4.485 kg b) 3.94 kg

Explanation:

since the maximum tension the line can stand is 44 N and for question a the speed is constant (acceleration must be zero since the velocity or speed is not changing), F(tension) = mass * acceleration due to gravity (g) .

44 = m * 9.81m/s^2

m = 44/9.81 = 4.485kg

b) F(tension) = ma + mg ( where a is the acceleration of the body and g is the acceleration of the gravity)

44 = m (a +g)

44 = m (1.37 + 9.81)

44/11.18 = m

m = 3.94 kg

3 0
3 years ago
Why is it important foe scientists to know how many valence electrons a given element has
Vikentia [17]
Because the number of valence electrons of an element determines the properties and in particular the reactivity of that element.

In fact, elements of the first group (i.e. only one valence electron) have high reactivity, because they can easily give away their valence electron to atoms of other elements forming bonds. On the contrary, elements of the 8th group (noble gases) have their outermost shell completely filled with electrons, so they do not have valence electrons, and they have little or no reactivity at all.
3 0
3 years ago
An amoeba has 1.00 x 1016 protons and a net charge of 0.300 pC. Assuming there are 1.88 x 106 fewer electrons than protons, If y
Xelga [282]

Answer:

The fraction of the protons would have no electrons =1.88\times 10^{-10}

Explanation:

We are given that

Amoeba has total number of protons=1.00\times 10^{16}

Net charge, Q=0.300pC

Electrons are fewer than protons=1.88\times 10^6

We have to find the fraction of protons would have no electrons.

The fraction of the protons would have no electrons

=\frac{Fewer\;electrons}{Total\;protons}

The fraction of the protons would have no electrons

=\frac{1.88\times 10^{6}}{1.00\times 10^{16}}

=1.88\times 10^{-10}

Hence, the fraction of the protons would have no electrons =1.88\times 10^{-10}

6 0
3 years ago
Other questions:
  • What kind of thermal transfer 1.conduction 2.convective 3.radiation from the sun?
    15·1 answer
  • If all else stays the same, which would cause an increase in the gravitational force on a space shuttle?
    14·2 answers
  • PLEASE HELP!!! Will give brainliest!
    5·2 answers
  • 7. Jezabelle was applying her makeup when she drove into Albuquerque migns busy
    14·1 answer
  • which is the of these their statements correctly describes a key difference between aerobic activity and anaerobic activity
    10·1 answer
  • Which of these experiments would make use of qualitative data?
    15·2 answers
  • I need help on the following questions.
    7·1 answer
  • Do you think ill look better in a french braid or a bun for a figure skating show.
    9·2 answers
  • Compare the different types of force?
    15·1 answer
  • How are traits influenced by the environment? (No links)
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!