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stepan [7]
3 years ago
6

A 30-cm long string, with one end clamped and the other free to move transversely, is vibrating in its second harmonic. The wave

length of the constituent traveling waves is:
Physics
1 answer:
Ann [662]3 years ago
5 0

Answer:

\lambda = 40 cm

Explanation:

given data

string length = 30 cm

solution

we take here equation of length that is

L = n \times \frac{1}{4} \lambda     ...............1

so

total length will be here

L = \frac{\lambda}{2} +  \frac{\lambda}{4}\\

L = \frac{3 \lambda }{4}

so \lambda  will be

\lambda = \frac{4L}{3}\\\lambda = \frac{4\times 30}{3}

\lambda = 40 cm

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