Question

A 30-cm long string, with one end clamped and the other free to move transversely, is vibrating in its second harmonic. The wavelength of the constituent traveling waves is:

Answer 1

Answer:

$\lambda$ = 40 cm

Explanation:

given data

string length = 30 cm

solution

we take here equation of length that is

L = $n \times \frac{1}{4} \lambda$     ...............1

so

total length will be here

$L = \frac{\lambda}{2} + \frac{\lambda}{4}$

$L = \frac{3 \lambda }{4}$

so $\lambda$  will be

$\lambda = \frac{4L}{3}\\\lambda = \frac{4\times 30}{3}$

$\lambda$ = 40 cm