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3 years ago

6

A 30-cm long string, with one end clamped and the other free to move transversely, is vibrating in its second harmonic. The wave

length of the constituent traveling waves is:

1 answer:

Ann [662]3 years ago

5 0

Answer:

$\lambda$ = 40 cm

Explanation:

given data

string length = 30 cm

solution

we take here equation of length that is

L = $n \times \frac{1}{4} \lambda$ ...............1

so

total length will be here

$L = \frac{\lambda}{2} + \frac{\lambda}{4}\\$

$L = \frac{3 \lambda }{4}$

so $\lambda$ will be

$\lambda = \frac{4L}{3}\\\lambda = \frac{4\times 30}{3}$

$\lambda$ = 40 cm

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An example of a negative incentive for producers is the sharp increase in production costs. Producers are the one who manage the production costs and even the production budget. Anything that relates the production department is entitled to the management of production producers.

There is what we called positive and negative incentives and both of these can affect consumers and producers. Positive incentives are those situations which will give a certain outcome that will benefit the producers, for example, during the peak season there will be a high demand of products, and this gives the chance of producers to demand a higher price from the consumers, in this situation, there will be a big chance of increase sales. A sharp increase in production costs is a loss for the producers. If there will be an increase in production costs, the budget will be greatly affective and even though it is not a peak season, there’s a big chance also to increase prices which we know, consumers are not fond of.

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3 years ago

How much tension must a rope withstand if it is used to accelerate a 6526 kg car vertically upwards at 8.9 m/s^2?

ExtremeBDS [4]

Answer:

The value is $T = 122036.2 \ N$

Explanation:

From the question we are told that

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Generally the net force applied on the rope is mathematically represented as

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3 years ago

A force of 10. N toward the right is exerted on a wooden crate initially moving to the right on a horizontal wooden floor. the c

Artyom0805 [142]

1) 5 N

The crate is initially moving, so we must calculate the force of kinetic friction, which is given by:

$F_f = \mu_k mg$

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Substituting the numbers into the formula, we find

$F_f=(0.2)(25 N)=5 N$

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There are two forces acting on the crate along the horizontal direction:

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Since the two forces are in opposite directions, the net force is given by their difference:

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2 years ago

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