Question:
Two 6.7 kg bodies, A and B, collide. The velocities before the collision are 
and 
. After the collision 
, 
. What are (a) the x-component and (b) the y-component of the final velocity of B? (c) What is the change in the total kinetic energy (including sign)?
Answer:
(a) 50 m/s
(b) 35.6 m/s
(c) -735.16 J
Explanation:
Given,
Change in kinetic energy = final kinetic energy - initial kinetic energy
If the particle's velocity were perpendicular to the magnetic field, the magnetic force would be given by:
F = qvB
F is the magnetic force, q is the charge, v is the velocity, and B is the magnetic field strength.
Given values:
F = 0.320N
q = 7.3×10⁻⁶C
v = 4×10⁵m/s
Plug in the values and solve for B:
0.320 = (7.3×10⁻⁶)(4×10⁵)B
B = 0.110T
The magnetic force depends on the cross product between the particle's velocity vector v and the magnetic field vector B. If v and B are parallel then the cross product is 0. v points in the +x direction, therefore B must point in either the +x or -x direction.
Answer:
P-value of the test statistic is 2.499
Explanation:
given data:
size sample is 24
sample mean is 414 gm
standard deviation is 15
Null hypotheis is
level of significance is 0.01
from test statics
degree od freedom is = n -1
df = 24 -1 = 13
t = -1.959
from t table critical value of t at 0.1 significane level and 23 degree of freedom is 2.499
