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3 years ago

How much will a 200kg hippo accelerate if you push it with a force of 800 N?

Physics

1 answer:

Fantom [35]3 years ago

4 0

Answer:

Explanation:

force = f, mass = m, acceleration = a

f = m a

m = 200 kg

f = 800 N

f = m a

800 = 200a

a = 800 / 200

Hope this helps

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Determine an appropriate size for a square cross-section solid steel shaft to transmit 260 hp at a speed of 550 rev/min if the m

Phantasy [73]

Answer:46.05 mm

Explanation:

Given

$Power=260\ hp\approx 260\times 746=193.96\ KW$

speed $N=550\ rev/min$

allowable shear stress $(\tau )_{max}=15\ kpsi\approx 103.421\ MPa$

Power is given by

$P=\frac{2\pi NT}{60}$

$193.96=\frac{2\pi 550\times T}{60}$

$T=3367.6\ N-m$

From Torsion Formula

$\frac{T}{J}=\frac{\tau }{r}-----1$

where J=Polar section modulus

T=Torque

$\tau$ =shear stress

For square cross section

$r=\frac{a}{2}$

where a=side of square

$J=\frac{a^4}{6}$

Substituting the values in equation 1

$\frac{3376.6}{\frac{a^4}{6}}=\frac{103.421\times 10^6}{\frac{a}{2}}$

$a=0.04605\ m$

$a=46.05\ mm$

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3 years ago

How long will it take to travel 200 000 m [North] traveling 10 m/s

Korvikt [17]

Answer:

there are 1,000m in a km, so 200km is 200,000m

200,000m/10m/s = 20,000s

Explanation:

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4 0

3 years ago

Find the kinetic energy of a 0.1-kilogram toy truck moving at the speed of 1.1 meters per second.

Viktor [21]

Answer:

0.061 J

Explanation:

The kinetic energy of an object is given by

$K=\frac{1}{2}mv^2$

where

m is the mass of the object

v is its speed

For the toy truck in the problem, we have

m = 0.1 kg is its mass

v = 1.1 m/s is its speed

Putting the numbers into the equation, we find

$K=\frac{1}{2}(0.1 kg)(1.1 m/s)^2=0.061 J$

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4 years ago

A DNA sequence is shown.

Katena32 [7]

Answer:

AAT-CAG-GT

AAT-CGA-GT

Explanation:

Because they are both missing one letter

6 0

3 years ago

Read 2 more answers

When the compressor of an air conditioner starts up, it draws a current of 50 A. If the start-up time is 0.60 s, then the amount

7nadin3 [17]

Answer:

30 C

Explanation:

Given:

Current flowing in the circuit (I) = 50 A

Start-up time (t) = 0.60 s

Now, we know that, charge drawn in through a cross sectional area of the circuit is given as:

$q=It$

Where, 'q' is the amount of charge drawn, 'I' is the current and 't' is the start-up time.

Now, plug in 50 A for 'I', 0.60 s for 't' and solve for 'q'. This gives,

$q=50\ A\times 0.60\ s\\\\q=30\ C$

Therefore, the amount of charge drawn in the circuit at the start-up of the compressor of an air conditioner is 30 C.

6 0

4 years ago