How much will a 200kg hippo accelerate if you push it with a force of 800 N?
1 answer:
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Answer:
Ratio will be
Explanation:
We have given that intensity level is increases from 23 dB to 61 dB
We know that level of intensity is given by
So ------eqn 1
And ------eqn 2
Subtracting eqn 1 from eqn 2
Answer:
<h2>a) 2.5 s</h2><h2>b) 1.55 m</h2><h2 />Explanation:
<h3>Given :-</h3><h2>Completes 2 oscillation in 5s.</h2><h2>A) Time period = ?</h2><h2 /><h2><em>Thus 1 oscillation is completed in 2.5 </em><em>s.</em>
<h2>B) If g = 9.8 ms−², find its length.</h2><h2>Thus the length of g = 9.8 ms −² = 1.55m
<h2>Hope it helps u.......</h2><h2>STAY SAFE, STAY HEALTHY AND BLESSED .</h2><h2> HAVE A MARVELOUS DAY AHEAD !</h2><h2>THANK YOU !</h2>Answer:
ωf = 8.8 rad/s
v = 2.2 m/s
Explanation:
We will use the third equation of motion to find the maximum angular velocity of the wheel:
where,
α = angular acceleration = 6 rad/s²
θ = angular displacemnt = 1 rev = 2π rad
ωf = max. final angular velocity = ?
ωi = initial angular velocity = 1.5 rad/s
Therefore,
<u>ωf = 8.8 rad/s</u>
Now, for linear velocity:
v = rω = (0.25 m)(8.8 rad/s)
<u>v = 2.2 m/s</u>