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3 years ago

What is the resultant acceleration?

Physics

2 answers:

Ksenya-84 [330]3 years ago

8 0

Answer: The sum of all the acceleration vectors. Hope this helps. :)

Explanation:

tatuchka [14]3 years ago

6 0

<h3>Answer</h3>

A option is the right option

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Which illustration represents the arrangement of particles in a gas?

Romashka [77]

Answer: the answer is c

Explanation:

just did it on ap3x

4 0

3 years ago

A sphere is filled with air. If the volume of the sphere is increasing at a rate of 569 cubic inches per minute, what is the rat

Veseljchak [2.6K]

Answer:565

Explanation:

6 0

3 years ago

Ordinarily, material presented ________ is usually the most difficult to remember due to interference

Brums [2.3K]

Memorizing items on a list are enabled by the effects of primacy and

recency.

Ordinarily, material presented <u>in the middle of a list </u> is usually the most

difficult to remember due to interference.

Reasons:

When memorizing a list of items, due to the primacy effect, the information

at the beginning of the list are given importance, in the brain, due to their

many attributes, which may be due to them being;

The first item

Definition of the task (assignment of importance level)

Idea of what to expect (preparation of the mind)

Also the last items on the list are recalled by the effect known as recency,

which is probably due to the tendency to store items in the short term

memory.

Therefore, in the course of memorizing a list, the first items on the list can

be stored in the long-term memory. The items that comes last in the

list are stored in the short-term memory, while the material presented in

the middle of the list are not allocated to a storage, and are usually

the most difficult to remember due to interference, by other items that

tend to come up during the retrieval process, from the long-term memory.

<em>(Rearranging the list can aid total recall)</em>

<em />

Learn more here:

brainly.com/question/15180534

<em>The possible question options as obtained from a similar question online, are;</em>

<em>At the beginning</em>
<em>Last</em>
<em>At the end</em>
<em>In the middle of a list</em>

5 0

2 years ago

Standing waves are set up on two strings fixed at each end, as shown in the drawing. The two strings have the same tension and m

uysha [10]

The beat frequency produced by the two standing waves is 13 Hz.

<h3>The wavelength of the shorter string</h3>

The wavelength of the shorter string is calculated as follows;

$L = \frac{\lambda}{2} \\\\\lambda = 2L\\\\\lambda = \frac{v}{f} \\\\\lambda = \frac{41.9}{225} \\\\\lambda = 0.186 \ m\\\\\lambda = 18.6 \ cm\\\\L= \frac{\lambda }{2} \\\\L = \frac{18.6 \ cm}{2} = 9.3\ cm$

<h3>The length of the longer string</h3>

$L_2 = 0.58 \ cm \ + 9.3 \ cm\\\\L_2 = 9.88 \ cm \\\\\lambda _2 = 2L_2\\\\\lambda _2 = 2(9.88 \ cm)\\\\\lambda_2 = 19.76 \ cm = 0.1976 \ m$

The frequency of the longer string is calculated as follows;

$v_1 = v_2\\\\f_2 = \frac{v_2}{\lambda_2} \\\\f_2 = \frac{41.9}{0.1976} \\\\f_2 = 212 \ Hz$

<h3>Beat frequency</h3>

The beat frequency produced by the two standing waves is calculated as follows;

$F_b = 225 \ Hz \ - \ 212 \ Hz\\\\F_b = 13 \ Hz$

Learn more about beat frequency here: brainly.com/question/3086912

8 0

3 years ago

One model for a certain planet has a core of radius R and mass M surrounded by an outer shell of inner radius R, outer radius 2R

Drupady [299]

(a) 120.8 m/s^2

The gravitational acceleration at a generic distance r from the centre of the planet is

$g=\frac{GM'}{r^2}$

where

G is the gravitational constant

M' is the mass enclosed by the spherical surface of radius r

r is the distance from the centre

For this part of the problem,

$r=R=1.17\cdot 10^6 m$

so the mass enclosed is just the mass of the core:

$M'=M=2.48\cdot 10^{24}kg$

So the gravitational acceleration is

$g=\frac{(6.67\cdot 10^{-11})(2.48\cdot 10^{24}kg)}{(1.17\cdot 10^6 m)^2}=120.8 m/s^2$

(b) 67.1 m/s^2

In this part of the problem,

$r=3R=3(1.17\cdot 10^6 m)=3.51\cdot 10^6 m$

and the mass enclosed here is the sum of the mass of the core and the mass of the shell, so

$M'=M+4M=5M=5(2.48\cdot 10^{24}kg)=1.24\cdot 10^{25}kg$

so the gravitational acceleration is

$g=\frac{(6.67\cdot 10^{-11})(1.24\cdot 10^{25}kg)}{(3.51\cdot 10^6 m)^2}=67.1 m/s^2$

8 0

4 years ago