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vodomira [7]
2 years ago
13

Please check if i did it right. did i put the right electric charge

Chemistry
1 answer:
Amiraneli [1.4K]2 years ago
3 0
Yes it’s correct your answer connect with eachother I did this before
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Elements donate 2 electron to produce a cation with a 2+ charge
hammer [34]

Answer: alkaline earth metals (group-IIA)

Explanation:

The element which donates the electron is known as electropositive element and forms a positively charged ion called as cation. The element which accepts the electrons is known as electronegative element and forms a negatively charged ion called as anion.

Alkaline earth metals donate 2 valence electrons to acquire noble gas configuration.

For example: Berrylium is the first alkaline earth metal with atomic number of 4 and thus has 4 electrons

Electronic configuration of berrylium:

[Be]:4:1s^22s^2

Berrylium atom will loose two electrons to gain noble gas configuration and form berrylium cation with +2 charge.

[Be^{2+}]:2:1s^2

Thus Elements donate 2 electron to produce a cation with a 2+ charge are alkaline earth metals.

5 0
3 years ago
A 50.00 L sample of gas collected in the upper atmosphere at a pressure of 18.30 torr is compressed into a volume of 0.1500 L. W
andreev551 [17]

Answer:

the ans is in the picture with the steps  

(hope it helps can i plz have brainlist :D hehe)

Explanation:

5 0
2 years ago
Be sure to answer all parts. provide stepwise mechanisms illustrating how each product is formed by choosing, in order, the step
SpyIntel [72]

Answer:

Explanation:

find the solution below

8 0
3 years ago
Identifying the single solution to a situation or problem is a crucial element of critical thinking. Please select the best answ
Marysya12 [62]

Answer: it is f

Explanation:

7 0
3 years ago
what is the empirical formula for a compound that is 50.61% copper 11.16% nitrogen and 38.23% oxygen
jonny [76]

Answer:

CuNO3

Explanation:

In order to calculate the empirical formula in this question;

Cu = 50.61% = 50.61g

N = 11.16% = 11.16g

O = 38.23% = 38.23g

Next, we convert each gram unit to moles by dividing by their respective molar mass (Where; Cu = 63.55, N = 14, O = 16)

Cu = 50.61 ÷ 63.55 = 0.796mol

N = 11.16 ÷ 14 = 0.797mol

O = 38.23 ÷ 16 = 2.389mol

Next, we divide each mole value by the smallest (0.796)

Cu = 0.796mol ÷ 0.796 = 1

N = 0.797mol ÷ 0.796 = 1.001

O = 2.389mol ÷ 0.796 = 3.001

Approximately, the simple whole number ratio between Cu, N and O is 1:1:3, hence, the empirical formula is CuNO3.

8 0
2 years ago
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