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nikklg [1K]
2 years ago
10

FRACTIONS PLS HELP NO LINKS

Mathematics
1 answer:
mojhsa [17]2 years ago
3 0

Answer:

One-eighth is equal to half of one-fourth.

Step-by-step explanation:

1/4 x 1/2 = 1/(4 x 2) = 1/8

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What is -2 times positive three
Elanso [62]

Answer:

-6

Step-by-step explanation:

You multiply -2 by 3 and you get -6.

2 negatives or 2 positives equals a positive number in Multiplication and Division.

But a Negative number and a positive number equals a negative number in Multiplication and Division.

3 0
3 years ago
Read 2 more answers
Given the sequence 7, 12, 17, 22, ...
abruzzese [7]

Answer:

option D is true.

Step-by-step explanation:

Given the sequence

7, 12, 17, 22, ...

An arithmetic sequence has a constant difference 'd' and is defined by

a_n=a_1+\left(n-1\right)d

Computing the differences of all the adjacent terms

12-7=5,\:\quad \:17-12=5,\:\quad \:22-17=5

The difference between all the adjacent terms is the same

so

d=5

as

a_1=7

Thus, the nth term of the arithmetic sequence will be:

a_n=5\left(n-1\right)+7

a_n=5n+2

Therefore, option D is true.

7 0
3 years ago
Two ways to write 15-b
GaryK [48]
The Answer: (-b + 15) (15 - b)
7 0
3 years ago
Find the area of the composite figure
Pavlova-9 [17]

Answer:

45

Step-by-step explanation:

4 0
3 years ago
Explain why a quadratic equation with a positive discriminant has two real solutions, a quadratic equation with a negative discr
Bad White [126]

Answer:

A quadratic equation can be written as:

a*x^2 + b*x + c = 0.

where a, b and c are real numbers.

The solutions of this equation can be found by the equation:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

Where the determinant is D = b^2 - 4*a*c.

Now, if D>0

we have the square root of a positive number, which will be equal to a real number.

√D = R

then the solutions are:

x = \frac{-b +- R }{2*a}

Where each sign of R is a different solution for the equation.

If D< 0, we have the square root of a negative number, then we have a complex component:

√D = i*R

x = \frac{-b +- C*i }{2*a}

We have two complex solutions.

If D = 0

√0 = 0

then:

x = \frac{-b +- 0}{2*a} = \frac{-b}{2a}

We have only one real solution (or two equal solutions, depending on how you see it)

3 0
3 years ago
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