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3 years ago

The compound Rh(CO)(H)(PH3)2 forms cis and trans isomers. Use this information

1 answer:

5 0

The geometry of a complex is determined by the number of ligands that surround the central atom/ion. There are four ligands in the complex. The coordination number of the complex is 4. The oxidation number of Rh is zero. The preferred geometrical shape of this complex is square planar.

Complexes are formed when Lewis bases called ligands become attached to a central metal atom or ion. The coordination number of the complex refers to the number of ligands that surround the central metal atom/ion.

In this case, four ligands surround the central Rhodium atom in a zero oxidation state.

Since we were told that the compound exhibits cis/trans isomerism then it can not have a tetrahedral geometry. It must have a square planar geometry as tetrahedral complexes do not exhibit cis/trans isomerism.

The image of the cis- and trans- geometrical isomers of the compound is attached to this answer.

Learn more: brainly.com/question/9616145

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A gas of unknown molecular mass was allowed to effuse through a small opening under constant-pressure conditions. It required 10

masya89 [10]

Answer: The molar mass of unknown gas is 367.12 g/mol

Explanation:

Rate of a gas is defined as the amount of gas displaced in a given amount of time.

$\text{Rate}=\frac{V}{t}$

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

So,

$\left(\frac{\frac{V_{X}}{t_{X}}}{\frac{V_{O_2}}{t_{O_2}}}\right)=\sqrt{\frac{M_{O_2}}{M_{X}}}$

We are given:

Volume of unknown gas (X) = 1.0 L

Volume of oxygen gas = 1.0 L

Time taken by unknown gas (X) = 105 seconds

Time taken by oxygen gas = 31 seconds

Molar mass of oxygen gas = 32 g/mol

Molar mass of unknown gas (X) = ? g/mol

Putting values in above equation, we get:

$\left(\frac{\frac{1.0}{105}}{\frac{1.0}{31}}\right)=\sqrt{\frac{32}{M_X}}\\\\M_X=367.12g/mol$

Hence, the molar mass of unknown gas is 367.12 g/mol

3 0

4 years ago

N2+ 3 H2 -> 2 NH3 If 12.0 g of H2 reacts with excess N2. then what mass of NH3 will be produced?

Vinil7 [7]

Hey mate here is pratyush for your help from India
..

your answer is in the attachment ..

the answer is 68g of NH3 will be produced.

hope it helps you.

be brainly

7 0

3 years ago

Helpp! is Au an element, compound, or mixture?

Stels [109]

Answer:

It's an element.

Explanation:

Au is gold. An "element " on the periodic table. Trust me. Im 100% sure.

7 0

3 years ago

Read 2 more answers

Highlight the significant figures and write the number of significant figures in the

White raven [17]

Explanation:

3. 4

4. 3

5. 3

6. 3

7. 2

8. 4

9. 2

10. 4

11. 6

12. 5

13. 7

14. 3

15. 5

5 0

2 years ago

German physicist Werner Heisenberg related the uncertainty of an object\'s position (Δx) to the uncertainty in its velocity Δv.

Assoli18 [71]

Heisenberg's Uncertainty Principle gives a relationship between the standard deviation of an object's position and its momentum.

$\Delta p \cdot \Delta x = h / (4 \pi)$ where

$\Delta p$ the standard deviation of the object's momentum,
$\Delta x$ the standard deviation of the object's position, and
$h \approx 6.63 \times 10^{-34} \; \text{J} \cdot \text{s}$ the Planck's constant.

By definition, the momentum of the electron equals the product of its mass and velocity.

$p = m\cdot v$

Assuming that measurement of the mass of the electron $m$ is accurate. It is assumed to be a coefficient of constant value. The standard deviation in the electron's velocity is thus directly related to that of its mass. That is:

$\Delta p = m \cdot \Delta v$

$\Delta v = 0.01 \times 10^{6} \;\text{m}\cdot \text{s}^{-1}$ from the question;

$\Delta p = m\cdot v \\ \phantom{\Delta p} = 0.01 \times 10^{6} \; \text{m} \cdot \text{s}^{-1} \times 9.11 \times 10^{-31} \; \text{kg}\\\phantom{\Delta p} = 9.11 \times 10^{-27} \; \text{kg} \cdot \text{m}\cdot \text{s}^{-1}$

Convert the unit of the Planck's constant to base SI units (kg, m, s, etc.) if it was provided in derived units such as joules. Doing so would allow for a dimension analysis on the accuracy of the result.

$h = 6.63 \times 10^{-34} \; \text{J} \cdot \text{s}\\\phantom{h} = 6.63 \times 10^{-34} \; (\text{N}\cdot \text{m}) \cdot \text{s} \\\phantom{h} = 6.63 \times 10^{-34} \; ((\text{kg} \cdot \text{m}\cdot \text{s}^{-2}) \cdot \text{m}) \cdot \text{s}\\\phantom{h} = 6.63 \times 10^{-34} \; \text{kg} \cdot \text{m}^{2} \cdot \text{s}^{-1}$

Apply the Uncertainty Principle:

$\Delta x = h/ (4 \pi \cdot \Delta p)\\\phantom{\Delta x} = 6.63 \times 10^{-34} \; \text{kg} \cdot \text{m}^{2} \cdot \text{s}^{-1} / (4 \pi \cdot 9.11\times 10^{-27} \; \text{kg} \cdot \text{m}\cdot \text{s}^{-1})\\\phantom{\Delta x} = 5.79 \times 10^{-9} \; \text{m}$ .

Dimensional analysis:

$\Delta x$ resembles the standard deviation of a position measurement. It is expected to have a unit of meter, which is the same as that of position.

3 0

3 years ago