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NISA [10]
4 years ago
6

Silicate particles from a construction site float through a heavily forested site and then make it into the upper troposphere wh

ere they become larger and gain a high organic carbon content. Explain what happened, with some reactions.
Chemistry
1 answer:
vivado [14]4 years ago
7 0

Answer:

There are two explanations to this: covalent network bonding and carbon-silicate cycle.

Explanation:

A network solid or covalent network solid is a chemical compound which is formed through a continued network of atoms or molecules held together by a covalent bond throughout the system. An example included C-C bond in graphite or C-Si bond in silicon carbide (tentative reaction equation below):

xSiO2 + yCO2→ SixCyO(2x+2y)

Si-Si bonds are not as strong as C-C bonds and can easily be displaced as the particles react with atmospheric CO2.

The second scenerio is when silicates such as calcium silicate CaSiO3, or wollastonite, reacts with atmospheric carbon dioxide and water to yield a calcium ion, Ca2+, a bicarbonate ion, HCO3-, and dissolved silica. This process occurs during carbon-silicate cycle and increase organic carbon content:

2CO2 + H2) + CaSiO3 → + SiO2CaCO3 + CO2 + H2)

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What is the difference between a transition metal and an f-element?
gtnhenbr [62]

Answer:  The transition elements are in the d-block, and in the d-orbital have valence electrons. They can form several states of oxidation and contain different ions. Inner transition elements are in the f-block, and in the f-orbital have valence electrons.

Explanation:

6 0
3 years ago
Find out no. of moles present is 72 gm of water?
Alona [7]
72g H2O x 1 mol H2O/18.02g H2O = 3.99 mol H2O 
8 0
3 years ago
In an experiment, mice were fed glucose (C₆H₁₂O₆) containing a small amount of radioactive carbon. The mice were closely monitor
Luden [163]
<h3>Answer:</h3>

Carbon dioxide

Explanation:

  • Cellular respiration involves a break down of sugars such as glucose to yield energy in the form of ATP and water together with carbon dioxide as byproducts.
  • In this case, when mice are fed with glucose, cellular respiration takes place breaking down glucose to yield energy in the form of ATP, water and carbon dioxide.
  • Therefore, the radioactive carbon in glucose showed up in carbon dioxide, since the carbon in glucose ends up in carbon dioxide.
8 0
3 years ago
In a science lab, Cash mixes two clear liquids together in a beaker. Bubbles are produced, and a white solid forms and settles t
Greeley [361]

Answer:

A chemical change occurred, a gas and precipitate was produced

Explanation:

From the question , we are informed of science lab, where Cash mixes two clear liquids together in a beaker. Bubbles are produced, and a white solid forms and settles to the bottom.

In this case the change that took place is chemical change ( is one where new product are formed after two substance react) the bubbles that is produced signify the presence of gas in the product, white solid formed is reffered to as a precipitate( which is reffered to as solid that is been formed from a particular solution).

5 0
3 years ago
Oxalic Acid, a compound found in plants and vegetables such as rhubarb, has a mass percent composition of 26.7% C, 2.24% H, and
blondinia [14]

Answer:

HCO₂

Explanation:

From the information given:

The mass of the elements are:

Carbon C = 26.7 g;     Hydrogen H = 2.24 g     Oxygen O = 71.1 g

To determine the empirical formula;

First thing is to find the numbers of moles of each atom.

For Carbon:

=26.7 \ g\times \dfrac{1 \ mol }{12.01 \ g} \\ \\ =2.22 \ mol \ of \ Carbon

For Hydrogen:

=2.24 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =2.22 \ mol \ of \ Hydrogen

For Oxygen:

=71.1 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =4.44 \ mol \ of \ oxygen

Now; we use the smallest no of moles to divide the respective moles from above.

For carbon:

\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ carbon

For Hydrogen:

\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ hydrogen

For Oxygen:

\dfrac{4.44 \ mol \ of \ Oxygen}{2.22} =2 \ mol \ of \ oxygen

Thus, the empirical formula is HCO₂

4 0
3 years ago
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