Answer:
See explanation
Explanation:
We know that photosynthesis involves the combination of carbon dioxide and water in the presence of sunlight to yield glucose.
If the atmosphere is rich in carbon dioxide such as in a green house where air is filled with carbon dioxide, the rate of photosynthesis is increased.
As the rate of photosynthesis is increased, the growth of plants is also increased.
Hence, in a greenhouse where the air contains more carbon dioxide, the rate of plant growth increases.
Answer:
A) A very thin atmosphere and temperatures vary from 427 degrees to -180 degrees Celsius (800 to -292 degrees Fahrenheit)
Explanation:
I did this quiz and this was the answer.
The balanced reaction: C2H6 + 7/2 O2 -> 2 CO2 + 3 H2O
We first convert volume of C2H6 to no. of moles. We use the conditions at STP where 1 mol = 22.4 L thus,
Moles C2H6 = 16.4 L/ 22.4 L =0.7321 mol
In order to determine the limiting reagent, we look at the given amounts of the reactants.
0.7321 mol C2H6 (7/2 mol O2 / 1 mol C2H6) = 2.562 mol O2
From the given amounts of the reactants, we can say that O2 is the limiting reactant since we need 2.562 mol O2 to completely react the given amount of C2H6. The excess reagent is C2H6
To calculate for the amount of products and excess reactants:
0.980 mol O2 (2 mol CO2 / (7/2 mol O2)) = 0.56 mol CO2 (22.4 L / 1 mol ) =12.544 L CO2
<span>0.980 mol O2 (1 mol C2H6 / (7/2 mol O2)) = 0.28 mol C2H6
Excess C2H6 = 0.7321 mol - 0.28 mol C2H6 = 0.4521 mol C2H6
We then use the molecular weight of C2H6 to convert the excess amount to grams.
0.4521 mol C2H6 (30.08 g C2H6 / 1 mol C2H6) = <span>13.60 g C2H6
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<span>Since the limiting reagent is O2 there will be no oxygen atoms that will be left after the reaction.</span>
Answer : Option 1) The true statement is each carbon-oxygen bond is somewhere between a single and double bond and the actual structure of format is an average of the two resonance forms.
Explanation : The actual structure of formate is found to be a resonance hybrid of the two resonating forms. The actual structure for formate do not switches back and forth between two resonance forms.
The O atom in the formate molecule with one bond and three lone pairs, in the resonance form left with reference to the attached image, gets changed into O atom with two bonds and two lone pairs.
Again, the O atom with two bonds and two lone pairs on the resonance form left, changed into O atom with one bond and three lone pairs. It concludes that each carbon-oxygen bond is neither a single bond nor a double bond; each carbon-oxygen bond is somewhere between a single and double bond.
Also, it is seen that each oxygen atom does not have neither a double bond nor a single bond 50% of the time.
Answer:
9 moles of N2
Explanation:
Well first you balance the equation which would be N2+3 H2>2 NH3. But you need 18 miles of NH3 so you would just replace the 2 moles of NH3 with 18 and balance the rest of the equation from there. And you would get 9 N2 + 27 H2>18 NH3
