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7nadin3 [17]
3 years ago
5

How many moles are in 75.0g of Na2CO3

Chemistry
1 answer:
emmasim [6.3K]3 years ago
8 0

Answer:

75g/106g = 0.71 moles

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Oxana [17]

Answer:

unequal heating and cooling of the landmass.

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The equilibrium constant, Kc, for the following reaction is 56.0 at 278 K. 2CH2Cl2(g) CH4(g) + CCl4(g) When a sufficiently large
BabaBlast [244]

Answer:

  • <u>21.5 M</u>

Explanation:

<u>1) Equilibrium equation (given):</u>

  • 2CH₂Cl₂ (g) ⇄ CH₄ (g) + CCl₄ (g)

<u>2) Write the concentration changes when some concentration, A, of CH₂Cl₂ (g) sample is introduced into an evacuated (empty) vessel:</u>

  • 2CH₂Cl₂ (g) ⇄ CH₄ (g) + CCl₄ (g)

           A - x                 x              x

<u>3) Replace x with the known (found) equilibrium concentraion of CCl₄ (g) of 0.348 M</u>

  • 2CH₂Cl₂ (g)   ⇄ CH₄ (g) + CCl₄ (g)

          A - 0.3485       0.348       0.348

<u>4) Write the equilibrium constant equation, replace the known values and solve for the unknown (A):</u>

  • Kc = [ CH₄ (g) ] [ CCl₄ (g) ] / [ CH₂Cl₂ (g) ]²

  • 56.0 = 0.348² / A²

  • A² = 56.0 / 0.348² = 462.

  • A = 21.5 M ← answer

7 0
3 years ago
What’s a predator? Are predators animals?
Setler [38]

Answer:

its an animal that preys on others

Explanation:

5 0
3 years ago
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The mode of 12, 17, 16, 14, 13, 16, 11, 14,13, 16 is​
RUDIKE [14]

Answer:

<h2>Mean = 14.2</h2><h2>Median = 14</h2><h2>Mode = 16</h2><h2>Range = 6</h2>

Explanation:

__________________________________________________________

<em>Mean = 14.2 or 14</em>

<em>Median = 14</em>

<em>Mode = 16</em>

<em>Range = 6</em>

<em>__________________________________________________________</em>

<em>Here are all the numbers from least to greatest order: 11, 12, 13, 13, 14, 14, 16, 16, 16, 17.</em>

<em>__________________________________________________________</em>

<em>Hope this helps! <3</em>

<em>__________________________________________________________</em>

8 0
3 years ago
Part
r-ruslan [8.4K]

The molar concentration will be greater than 0.01 M KIO_{3}.


Since more of the compound was measured out than what was calculated, you can think of the solution as being 'stronger' than what it was calculated to be. Since a 'stronger' concentration results in a number that is higher, the molarity of this solution is going to be greater than 0.01 M.

7 0
3 years ago
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