Does anyone know this??

Chemistry

1 answer:

soldier1979 [14.2K]3 years ago

3 0

Answer:

9 moles of N2

Explanation:

Well first you balance the equation which would be N2+3 H2>2 NH3. But you need 18 miles of NH3 so you would just replace the 2 moles of NH3 with 18 and balance the rest of the equation from there. And you would get 9 N2 + 27 H2>18 NH3

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If one lightbulb burns out, but the other bulbs remain lit, the circuit must be a

Solnce55 [7]

Answer:

Parallel Circuit

Explanation:

In a parallel circuit, there are multiple paths through which the current can flow, so the resistance of the overall circuit is lower than it would be if only one path was available.

7 0

3 years ago

How many moles of Mg(OH)2(aq) would be required to neutralize 6.0 mol HCl(aq)?

jekas [21]

Answer:

$3.0molMg(OH)_2$

Explanation:

Hello there!

In this case, for these types of acid-base neutralizations, it is crucial to firstly set up the chemical reaction taking place between the acid and the base; in this case HCl and Mg(OH)2 respectively, whose products are obtained by switching around the anions and cations as shown below:

$HCl(aq)+Mg(OH)_2(aq)\rightarrow MgCl_2(aq)+H_2O(l)$

Which must be balanced to accurately predict the mole ratio on the reactants side:

$2HCl(aq)+Mg(OH)_2(aq)\rightarrow MgCl_2(aq)+2H_2O(l)$

Whereas we can see a 2:1 mole ratio of the acid to the base; thus, the moles of Mg(OH) required for the neutralization of 6.0 moles of HCl turn out to be:

$6.0molHCl*\frac{1molMg(OH)_2}{2molHCl} \\\\=3.0molMg(OH)_2$