Answer:In a sample of BrF the strongest interparticle force is the dipole-dipole force.
While Kr is the dispersion force.
And H2SO4 is hydrogen bonding
Explanation:
Brf is polar with a known dipole moment of 1.4D,dipole - dipole force and dispersion force are both present,the dipole-dipole force is the strongest interparticle force action on Brf considering its high boiling points
The bond formed by Kr will be non polar due to greater atomic size and low electronegativity.The force of attraction between the non polar is the dispersion force which is the strongest.
H2SO4 has a great polarity with a very strong hydrogen bonding.
Answer:
Element x has an atomic number of 16, it is sulphur.
Element Y has an atomic number of 20, it is calcium.
i) Sulphur is in Group VI, period 3 in the modern periodic table,
whereas calcium is in Group II, period 4 of the modern periodic table.
ii) Ionic bonds will form between them. This is because metals and non-metals (Cacium and sulphur) usually form ionic compounds where between the ions are held by ionic bonds (which are transferred electrons so that both elements can attain a stable status).
iii) CaS
each Calcium atom can lose 2 electrons to attain 8 outermost shell electrons, while each sulphur atom can gain the 2 electrons to attain 8 outermost shell electrons, where they will most be stable (octet). Hence, the atomic ratio of Ca and S is 1:1.
No because the limiting reactant is determined by calculating the amount of product therefore the limiting reactant will not be the same for a given reaction
Answer:
3.18 g of lead sulfate is produced in this reaction
Explanation:
The reaction is this one:
Na₂SO₄ (aq) + Pb(NO₃)₂ (aq) → 2 NaNO₃ (aq) + PbSO₄ (s)
Let's determine the moles of reactants, to find out which is the limiting.
Molarity . volume = Mol
0.105 m/L . 0.100L = 0.0105 moles of sulfate
0.985 m/L . 0.100L = 0.0985 moles of nitrate
Ratio is 1:1, so 1 mol of sulfate needs 1 mol of nitrate, to react.
0.0985 moles of nitrate need 0.0985 moles of sulfate to react, but I only have 0.0105 moles so the sulfate is my limiting reactant.
Ratio is again 1:1, so 0.0105 moles of sulfate make 0.0105 moles of lead sulfate.
Mol . molar mass = mass → 0.0105 mol . 303.26 g/m = 3.18 g
