3 years ago

If m2WXY =160º, what are m2WXZ and mZZXY? Z (5x+2) (77-4) w

Mathematics

1 answer:

uysha [10]3 years ago

7 0

Answer:

87, 73 (solution A)

Step-by-step explanation:

We know that angle WXY is 160 degrees. Therefore, (5x+8)+(7x-4)=160.

(5x+8)+(7x-4)=160

5x+8+7x-4=160

12x=156

x=13

Now that we have x, we can plug them in to the expressions to find the measures of the given angles.

7(13)-4=87 degrees (angle WXZ)

5(13)+8=73 degrees (angle YXZ)

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