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Lapatulllka [165]
3 years ago
6

Two positively charged objects (N pole) are separated by a large distance. One of the positively charged objects (N pole) is rep

laced by a negatively charged object (S pole), and the two objects are moved closer to each other.Which of the following occurs in this situation?AThe attractive force becomes a repulsive force, which increases as the objects move closer to each otherBThe repulsive force becomes an attractive force, which increases as the objects move closer to each other.CThe attractive force becomes a repulsive force, which decreases as the objects move closer to each other.DThe repulsive force becomes an attractive force, which decreases as the objects move closer to each other.
Chemistry
1 answer:
Eddi Din [679]3 years ago
6 0

Answer:

B

Explanation:

Applying law of electrostatic which states that like charges repel each other and unlike charges attract each other

N and S are unlike charges that turn and make the former repulsive force (due to two like charges N and N)to <em>reduce</em> and attractive force between N and S to <em>increa</em><em>se</em>

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chegg write a net ionic equation describing the oxidation of no2 2 to no3 2 by o2 in a basic solution.
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When the same species undergoes both oxidation and reduction in a single redox reaction, this is referred to as a disproportionation. Therefore, divide it into two equal reactions.

NO2→NO^−3

NO2→NO

and do the usual changes

First, balance the two half reactions:

3. NO2 +H2O →NO^−3 + 2 H^+ + e−

4. NO2 +2 H^+ + 2e− → NO + H2O

Now multiply one or both half-reactions to ensure that each has the same number of electrons. Here, Eqn (3) x 2 results in each half-reaction having two electrons:

5. 2 NO2 + 2 H2O → 2 NO^−3 + 4H^+ + 2e−

Now add Eqn 4 and 5 (the electrons now cancel each other):

3NO2 + 2H^+ + 2H2O → NO + 2 NO−3 + H2O + 4H+

and cancel terms that’s common to both sides:

3NO2 + H2O → NO + 2NO^−3 + 2H+

This is the net ionic equation describing the oxidation of NO2 to NO3 in basic solution.

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7 0
1 year ago
Magnesium oxide (MgO) forms when the metal burns in air. (a) If 1-25 9 of MgO contains 0.754 g of Mg, what is the mass ratio of
Vsevolod [243]

Answer:

Explanation:

a )

1.25 g MgO contains .754 g of Mg .Rest will be O

so oxide = 1.25 - .754 = 0.496 g

ratio of magnesium to oxide = .754/.496 = 1.52

b) 1.25 g of MgO contains .754 g of Mg

534 g of MgO contains .754 x 534 / 1.25 g = 322.11 g

5 0
3 years ago
Determine the mass of the H2CO3 produced.
FrozenT [24]

Answer:

62.03 g/mol

Explanation:

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NEED ANSWER ASAP!<br> How many grams are in 1.50 moles of bromine liquid?
padilas [110]

Answer:

119.85 grams Br or 120. grams Br (sig figs)

Explanation:

1.50 moles Br          79.90 g Br

--------------------- x ------------------------ = 119.85 grams Br or 120 grams Br (sig figs)

                                     1 mole

7 0
3 years ago
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