Answer:
Mass percent of Mn is 34.76 %
Explanation:
<em>Mass percent</em> of an element is the mass of that element divided by the total mass of the elements forming that compound (or molecular mass.
So,
Mass percent of Mn will be given as,
%Mn = Atomic Mass of Mn / Molecular Mass of KMnO₄ × 100
So,
Atomic Mass of Mn = 54.94 g/mol
Molecular Mass of KMnO4 = 158.034 g/mol
Putting values in above formula,
%Mn = 54.94 g/mol ÷ 158.034 g/mol × 100
%Mn = 34.76 %
Answer: m = 50 g ZnSO4
Explanation: First is convert the moles of Zn to the moles of ZnSO4 by having their mole ratio which is 2:2 based from the balanced equation. Next is convert the moles of ZnSO4 to mass using its molar mass.
0.311 mole Zn x 2 moles ZnSO4 / 2 moles Zn
= 0.311 moles ZnSO4
0.311 moles ZnSO4 x 161 g ZnSO4 / 1 mole ZnSO4
= 50 ZnSO4
