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Elden [556K]
3 years ago
11

A circular loop of radius 5 cm carries a current of 5A, it has a uniform magnetic field of 2,0T. Calculate the magnetic force on

the loop.
Physics
1 answer:
pshichka [43]3 years ago
4 0

Answer:

F = BIl

F » magnetic force

B » magnetic flux density

l » length / circumference

F = BI(2\pi r)

r » radius

F = 2 \times 5 \times (2 \times 3.14 \times 0.05) \\ { \underline{force = 3.14 \:  \: newtons}}

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Answer:

F=7.7\times10^2 N

Explanation:

The magnitude of force required to pull the lid off the box by air pressure.

We know that Pressure, P= Force(F)/Area(A)

Force, F= P×A

Given: A=1.10\times10^{-2} m^2

P=7\times10^{4} Pa.

Therefore, F=7\times10^{4}\times1.10\times10^{-2}.

F=7.7\times10^2 N

4 0
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What are two differences between gravity and air resistance
Natalka [10]

1. Air resistance force usually upwards, but gravity doenwards.

2. Objects are affected by gravity the same, but air resistance can affect the speed of an object's descent.

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4 0
3 years ago
Producing a current by moving a wire through a magnetic field is called “BLANK” induction
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Producing a current by moving a wire through a magnetic field is called ELECTROMAGNETIC INDUCTION.
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3 0
3 years ago
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A certain kind of glass has an index of refraction of 1.660 for blue light of wavelength 420 nm and an index of 1.630 for red li
Bogdan [553]

Answer:

Explanation:

Using Snell's law

n₁ sinθ₁ = n₂ sinθ₂

for 420 nm wavelength

where n₁ = 1.00 ( refractive index of air) and θ₁ = 30° n₂ = 1.660

1.00 × sin 30° = 1.660 sinθ₂

sinθ₂ = 0.3012

θ₂ = sin⁻¹ 0.3012 = 17.53°

for 690 nm wavelength

n₁ sinθ₁ = n₂ sinθ₂

sinθ₂ = 0.5 / 1.630

θ₂ = sin⁻¹ 0.3067 = 17.86°

the angle between the two beam = 17.863° - 17.53° = 0.333°

7 0
3 years ago
A speedy rabbit is hopping to the right with a velocity of 4.0 \,\dfrac{\text m}{\text s}4.0 s m ​ 4, point, 0, start fraction,
Mrrafil [7]

Answer: 38.25 m

Explanation:

In this situation we need to find the distance d between the rabbit and the carrot, and we can use the following equation, since the rabbit's acceleration is constant:

V^{2}=V_{o}^{2} + 2ad (1)

Where:

V=13 m/s is the rabbit's maximum velocity (final velocity)

V_{o}=4 m/s is the rabbit's initial velocity

a=2 m/s^{2} is the rabbit's acceleration

d is the distance between the rabbit and the carrot

Isolating d:

d=\frac{V^{2}-V_{o}^{2}}{2a} (2)

d=\frac{(13 m/s)^{2}-(4 m/s)^{2}}{2(2 m/s^{2})} (3)

Finally:

d=38.25 m

8 0
4 years ago
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