A pendulum has 895 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o
1 answer:
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Answer:
Work done, W = 8 J
Explanation:
We have,
Force acting on the cart is 4 N
Cart covers a distance of 2 m
We need to find the work done by the cart. Work done by an object is given in terms of force and displacement. It can be given by :
So, the work done by the cart is 8 J.
Answer:
A) C_{eq} = 15 10⁻⁶ F, B) U₃ = 3 J, U₄ = 0.5 J
Explanation:
In a complicated circuit, the method of solving them is to work the circuit in pairs, finding the equivalent capacitance to reduce the circuit to simpler forms.
In this case let's start by finding the equivalent capacitance.
A) Let's solve the part where C1 and C3 are. These two capacitors are in serious
(you has an mistake in the formula)
= 0.1 10⁶
= 10 10⁻⁶ F
capacitors C₂, C₄ and C₅ are in series
= 0.2 10⁶
= 5 10⁻⁶ F
the two equivalent capacitors are in parallel therefore
C_{eq} = C_{eq1} + C_{eq2}
C_{eq} = (10 + 5) 10⁻⁶
C_{eq} = 15 10⁻⁶ F
B) the energy stored in C₃
The charge on the parallel voltage is constant
is the sum of the charge on each branch
Q = C_{eq} V
Q = 15 10⁻⁶ 6
Q = 90 10⁻⁶ C
the charge on each branch is
Q₁ = Ceq1 V
Q₁ = 10 10⁻⁶ 6
Q₁ = 60 10⁻⁶ C
Q₂ = C_{eq2} V
Q₂ = 5 10⁻⁶ 6
Q₂ = 30 10⁻⁶ C
now let's analyze the load on each branch
Branch C₁ and C₃
In series combination the charge is constant Q = Q₁ = Q₃
U₃ =
U₃ =
U₃ = 3 J
In Branch C₂, C₄, C₅
since the capacitors are in series the charge is constant Q = Q₂ = Q₄ = Q₅
U₄ =
U₄ = 0.5 J
Answer:
Explanation:
Given that:
Height of jump,
length of elastic cord,
spring constant of the cord,
mass of the body that jumps,
Force on the bungee elastic cord:
Now this force F will be responsible for the elongation in the elastic cord, so:
............................(1)
where :
k = spring constant
x = extension in the elastic cord
using eq. (1)
So the cord stretches 19.6 meters more beyond its original length of 30 meters.
Hence, the remaining distance from the river surface at the bottom is: