1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
emmainna [20.7K]
3 years ago
5

A certain kind of glass has an index of refraction of 1.660 for blue light of wavelength 420 nm and an index of 1.630 for red li

ght of wavelength 690 nm. If a beam containing these two colors is incident at an angle of 30.0° on a piece of this glass, what is the angle between the two beams inside the glass?
Physics
1 answer:
Bogdan [553]3 years ago
7 0

Answer:

Explanation:

Using Snell's law

n₁ sinθ₁ = n₂ sinθ₂

for 420 nm wavelength

where n₁ = 1.00 ( refractive index of air) and θ₁ = 30° n₂ = 1.660

1.00 × sin 30° = 1.660 sinθ₂

sinθ₂ = 0.3012

θ₂ = sin⁻¹ 0.3012 = 17.53°

for 690 nm wavelength

n₁ sinθ₁ = n₂ sinθ₂

sinθ₂ = 0.5 / 1.630

θ₂ = sin⁻¹ 0.3067 = 17.86°

the angle between the two beam = 17.863° - 17.53° = 0.333°

You might be interested in
A 0.106-A current is charging a capacitor that has square plates 6.00 cm on each side. The plate separation is 4.00 mm. (a) Find
FrozenT [24]

Answer:

The time rate of change of flux is 1.34 \times 10^{10} \frac{V}{s}

Explanation:

Given :

Current I = 0.106 A

Area of plate A = 36 \times 10^{-4} m^{2}

Plate separation d = 4 \times 10^{-3} m

(A)

First find the capacitance of capacitor,

   C = \frac{\epsilon _{o} A }{d}

Where \epsilon _{o} = 8.85 \times 10^{-12}

   C = \frac{8.85 \times 10^{-12 } \times 36 \times 10^{-4}  }{4 \times 10^{-3} }

   C = 7.9 \times 10^{-12} F

But   C = \frac{Q}{V}

Where Q = It

  C = \frac{It}{V}

  V = \frac{It}{C}

Now differentiate above equation wrt. time,

  \frac{dV}{dt} = \frac{I}{C}

       = \frac{0.106}{7.9 \times 10^{-12} }

       = 1.34 \times 10^{10} \frac{V}{s}

Therefore, the time rate of change of flux is 1.34 \times 10^{10} \frac{V}{s}

8 0
3 years ago
The ____ of a position-time graph represents an object’s velocity.
Marianna [84]

Answer:

The slope of a position-time graph represents an object’s velocity.

Explanation:

In a position-time graph, the values on the x-axis represent the time, while the values on the y-axis represent the position of the object.

Velocity is defined as the ratio between the displacement of an object and the time taken:

v=\frac{\Delta s}{\Delta t}

However, we can see that this definition corresponds to the slope of the curve in a position-time graph. In fact:

\Delta s, the displacement, corresponds to the difference in position, so the difference between the values on the y-axis: \Delta s=y_2 -y_1

\Delta t, the time interval, corresponds to the difference in times, so the difference between the values on the x-axis: \Delta t= t_2 -t_1=x_2 -x_1

So, the velocity is

v=\frac{\Delta s}{\Delta t}=\frac{y_2 -y_1}{x_2 -x_1}

which corresponds to the slope of the curve.

3 0
3 years ago
Read 2 more answers
HEY CAN ANYONE HELP ME OUT IN DIS RQ!!!!!!
shusha [124]

Answer:

40 laps

Explanation:

400/10=40

8 0
3 years ago
A fullback preparing to carry the football starts from rest and accelerates straight ahead. He is handed the ball just before he
RideAnS [48]

Answer:

x=4.06m

Explanation:

A body that moves with constant acceleration means that it moves in "a uniformly accelerated movement", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.

Vf=Vo+a.t  (1)\\\\

{Vf^{2}-Vo^2}/{2.a} =X(2)\\\\

X=Xo+ VoT+0.5at^{2}    (3)\\

Where

Vf = final speed

Vo = Initial speed

T = time

A = acceleration

X = displacement

In conclusion to solve any problem related to a body that moves with constant acceleration we use the 3 above equations and use algebra to solve

for this problem

Vf=7.6m/s

t=1.07

Vo=0

we can use the ecuation number one to find the acceleration

a=(Vf-Vo)/t

a=(7.6-0)/1.07=7.1m/s^2

then we can use the ecuation number 2 to find the distance

{Vf^{2}-Vo^2}/{2.a} =X

(7.6^2-0^2)/(2x7.1)=4.06m

4 0
4 years ago
How can a scientist ensure that his or her data are reliable?
laiz [17]
If the scientist repeats the experiment over and over and gets the same results. Also if the scientist peer reviews the experiment to make sure there is no bias in his or her results.

7 0
3 years ago
Read 2 more answers
Other questions:
  • A 25-kg child sits at the top of a 4-meter slide. After sliding down, the child is traveling at 5 m/s. How much PE does he start
    15·1 answer
  • Vector A→ has a magnitude of 8 units and makes an angle of 45° with the positive x-axis. Vector B→ also has a magnitude of 8 uni
    5·2 answers
  • What goes through evaporation
    9·2 answers
  • A swimmer standing near the edge of a lake notices a cork bobbing in the water. While watching for one minute, she notices the c
    10·1 answer
  • What is reference point
    9·1 answer
  • Which statement describes a resistor in a circuit?
    15·2 answers
  • It took 3.5 hours for a train to travel the distance between two cities at a velocity
    5·1 answer
  • The movement of water between the atmosphere, land, oceans, and even living things makes up the water cycle. Precipitation is on
    8·1 answer
  • What is most likely the amount of energy available at a trophic level of primary consumers if the amount of energy available to
    12·1 answer
  • Please answer B, C, E, and D
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!