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julsineya [31]
3 years ago
11

HELP DUE IN 10 MINUTES WILL GIVE BRAINLEST!!

Mathematics
2 answers:
Pachacha [2.7K]3 years ago
5 0

y-intercept: (0, 7)

x-intercept: (-\frac{7}{4},0)\\

steposvetlana [31]3 years ago
5 0
X=-7/4
Y=7

^^^ right there
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Katyanochek1 [597]
9,500  just add the 0 always add 0 if you multiply by 10. 00 for 100 and 000 for 1000
7 0
3 years ago
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I NEED HELP IDENTIFYING THE SLOPE PLEASE !!! Pic attatched !!!!
Alexus [3.1K]

Answer:

see explanation

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = 2,4 ) and (x₂, y₂ ) = (5, 1)

m = \frac{1-4}{5-2}  = \frac{-3}{3} = - 1 ← negative slope

Repeat

with (x₁, y₁ ) = - 7,8) and (x₂, y₂ ) = (- 7, 0)

m = \frac{0-8}{-7+7} = \frac{-8}{0}

Division by zero is undefined, thus slope is undefined.

Repeat with

(x₁, y₁ ) = (6, - 3) and (x₂, y₂ ) = (- 4, - 3)

m = \frac{-3+3}{-4-6} = \frac{0}{-10} = 0 ← zero slope

Repeat with

(x₁, y₁ ) = (3, 5) and (x₂, y₂ ) = (- 1, 2)

m = \frac{2-5}{-1-3} = \frac{-3}{-4} = \frac{3}{4} ← positive slope

7 0
3 years ago
It takes 10 hours to type 4 reports how many hours does it take to type 15 reports
yaroslaw [1]

Answer:37.5 hrs

Step-by-step explanation:

15/4 = 3.75

3.75*10=37.5

6 0
2 years ago
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Given that sec (x) = 2 and cosec (x) is negative,
weeeeeb [17]

Answer:

i) sin(2x) = -\frac{\sqrt{3}}{2}

ii) cot(x+360) = -\frac{\sqrt{3}}{3}

iii) sin(x-180) = \frac{\sqrt{3}}{2}

Step-by-step explanation:

sec(x) = 2

Since cos(x) is reciprocal of sec(x), this means:

cos(x) = \frac{1}{2}

cosec(x) is negative , this means sin(x) is also negative. The only quadrant where cos(x), sec(x) are positive and sin(x), cosec(x) are negative is the 4th quadrant. Hence the terminal arm of the angle x is in 4th quadrant.

Part i)

sin(2x) can be simplified as:

sin(2x) = 2 sin(x) cos(x)

First we need to find the value of sin(x). According to Pythagorean identity:

sin^{2}(x)=1-cos^{2}(x)\\\\ sin(x)=\pm \sqrt{1-cos^{2}(x)}

Since, angle is in 4th quadrant, sin(x) will be negative. So considering the negative value of sin(x) and substituting the value of cos(x), we get:

sin(x)=- \sqrt{1-cos^{2}(x)}\\\\ sin(x)=-\sqrt{1-(\frac{1}{2})^{2}}\\\\ sin(x)=-\frac{\sqrt{3}}{2}

So,

sin(2x)=2 \times -\frac{\sqrt{3} }{2} \times \frac{1}{2}\\\\ sin(2x)=-\frac{\sqrt{3}}{2}

Part ii)

We have to find cot(x + 360)

An addition of 360 degrees to the angle brings it back to the same terminal point. So the trigonometric ratios of the original angle and new angle after adding 360 or any multiple of 360 stay the same. i.e.

cot(x + 360) = cot(x)

cot(x) = \frac{cos(x)}{sin(x)}\\

Using the values, we get:

cot(x)=\frac{\frac{1}{2}}{-\frac{\sqrt{3}}{2} }\\\\ cot(x)=-\frac{\sqrt{3}}{3}

Part iii)

We need to find the value of sin(x - 180)

sin(x - 180) = - sin(x)

Addition or subtraction of 180 degrees changes the angle by 2 quadrants. The sign of sin(x) becomes opposite if the angle jumps by 2 quadrants. For example, sin(x) is positive in 1st quadrant and negative in 3rd quadrant.

So,

sin(x - 180) = -(-\frac{\sqrt{3}}{2}) = \frac{\sqrt{3}}{2}

6 0
3 years ago
Find the GCF of 32 and 72
Ilya [14]

Answer:

8

Step-by-step explanation:

Hope this helps :)

3 0
3 years ago
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