The probability that all of them will be defective is 0.0000759375
<em><u>Explanation</u></em>
The general <u>Binomial Probability</u> formula is....
, where p is the probability of success, n is the total number of trials and r is the desired numbers of trials.
Given, the probability that a computer will be defective is 0.15 , so p = 0.15
Five computers are manufactured and we need to find the probability that all of them will be defective. That means, n = 5 and r = 5
Now according to the above formula....

So, the probability that all of them will be defective is 0.0000759375
So,
53,879 rounded to the nearest hundred:
If the number in the tens place is greater than or equal to 5, then round up. If not, round down.
7 is greater than or equal to 5, so round up.
53,879 --> 53,900
the radius: r^2 = 81
r =9
c = 2*pi*r
= 2 * pi * 9
= 18 *pi
Answer: 18*pi or approximately 56.62
Answer:
The value of x is ![2\sqrt[3]{2}](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B2%7D)
Step-by-step explanation:
We are given 
We need to solve for x
First we subtract 2 both sides

Taking cube roots both sides to isolate x
![x=\sqrt[3]{16}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B16%7D)
Simplify the radical
![x=2\sqrt[3]{2}](https://tex.z-dn.net/?f=x%3D2%5Csqrt%5B3%5D%7B2%7D)
Thus, The value of x is ![2\sqrt[3]{2}](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B2%7D)