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larisa [96]
3 years ago
15

Find the product: [2 7][-3 7]= [a b ] [1 3 ][1 -2] [ c d] a= b= c= d=

Mathematics
1 answer:
Vsevolod [243]3 years ago
7 0

Answer:

idont ow ask juesuslolllolol,

Step-by-step explanation:

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Find the value of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B35%20%2B%201%7D%20" id="TexFormula1" ti
aliya0001 [1]
Answer is 6 if you do 35+1 that gives you 36, the square root of 36 is 6 .6•6=36 so that’s your answer 6
6 0
3 years ago
Read 2 more answers
What is the additive inverse of the complex number 9 â€"" 4i? â€""9 â€"" 4i â€""9 4i 9 â€"" 4i 9 4i.
hram777 [196]

Additive inverse is the number you add to a given number to make the sum zero. The addition of both the number must be zero to make both numbers additive inverse.. The additive inverse of the given complex number is

-9+4i

<h3>Addictive Inverse</h3>

Addictive Inverse-Additive inverse is the number you add to a given number to make the sum zero. The addition of both the number must be zero to make both numbers additive inverse.

Let an example, if we take the number 10 and add -10 to it. Thus -10 is the additive inverse of the number 10.

Here, the given number is a complex number. A complex number is a number of the form a + bi, where a and b are real numbers. The given function is,

9-4i

The additive inverse of the above number is,-9+4i

Add both and check by equating with zero,

9-4i+(-9i+4)=0

9-4i+-9i+4=0

0=0

Hence, the additive inverse of the given complex number is -9+4i.

For more about the additive inverse, follow the link below-brainly.com/question/13715269

5 0
2 years ago
Read 2 more answers
-4&lt;3x+5(less than or equal to) 11
Free_Kalibri [48]

Answer:

-3<x<=2

Step-by-step explanation:

-4<3x+5<=11

-5       -5     -5

<u>-9<3x<=6</u>

3   3      3

-3<x<=2

5 0
3 years ago
Solve x<br>2x+<br><img src="https://tex.z-dn.net/?f=2x%20%2B%20%20%5Csqrt%7B10%20-%20x%20%7C%20%7D%20%20%3D%20%20-%201" id="TexF
AleksandrR [38]

Answer: x = -(9/4)

Step-by-step explanation:

7 0
3 years ago
Give me a correct answer, My answer probably wrong.
Georgia [21]

Hello!

This is a problem about the general solution of a differential equation.

What we can first do here is separate the variables so that we have the same variable for each side (ex. dy with the y term and dx with the x term).

\frac{dy}{dx}=\frac{x-1}{3y^2}

3y^2dy=x-1dx

Then, we can integrate using the power rule to get rid of the differentiating terms, remember to add the constant of integration, C, to at least one side of the resulting equation.

y^3=\frac{1}{2}x^2-x+C

Then here, we just solve for y and we have our general solution.

y=\sqrt[3]{\frac{1}{2}x^2-x+C}

We can see that answer choice D has an equivalent equation, so answer choice D is the correct answer.

Hope this helps!

3 0
3 years ago
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