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bezimeni [28]
3 years ago
13

HELP ME PLSSSSSSSSSSSSSSSSS​

Mathematics
1 answer:
9966 [12]3 years ago
7 0

4 \times 10 {}^{6}  + 7 \times  {10}^{5}  + 2 \times  {10}^{4}  + 3 \times  {10}^{3}   + 9 \times  {10}^{2}  + 1 \times  {10}^{1}  + 0 \times   {10}^{0}

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What is 6 divided by 0.6
slava [35]

Answer:

10

Step-by-step explanation:

the answer is 10

7 0
3 years ago
A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the
nalin [4]

Answer:

$519

Step-by-step explanation:

Given the amount of profit made expressed as y=-2x^2+105x-859

At maximum profit, dy/dx = 0

dy/dx = -4x + 105

0 = -4x + 105

4x = 105

x = 105/4

x = 26.25

Substitute into the original function

y=-2x^2+105x-859

y=-2(26.25)^2+105(26.25)-859

y = - 1,378.125+2,756.25-859

y = 519.125

Hence the maximum amount of profit the company can make is $519

8 0
3 years ago
The mean of 15 numbers is y.If each of the number is increased by 30, find the increase of the new mean in terms of y.The answer
dusya [7]

Answer:

y+30

Step-by-step explanation:

the sum of the numbers is 15y

the new sum after increase each number by 30 is 15y+450

the new mean 15y+450/15

= y+30

4 0
3 years ago
Write a real word problem that involves finding the product of 3/4 and 1/8
jekas [21]
A carpenter wants you to find the surface area of a shelf top. The length of the shelf is 3/4 m and the depth is 1/8 m.
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3 years ago
Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 b
jeka94

Answer:

Step-by-step explanation:

From the given information; Let's assume that  R should represent the set of all possible outcomes generated from  a bit string of length 10 .

So; as each place is fitted with either 0 or 1

\mathbf{|R|= 2^{10}}

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0

Now;

if  a 0 bit and a 1 bit are equally likely

The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

\mathbf{P(E) = \dfrac{|E|}{|R|}}

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:

\mathbf{{|E|}=1 }   ; \mathbf{|R|= 2^{10}}

\mathbf{P(E) = \dfrac{1}{2^{10}}}

4 0
3 years ago
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