The molar heat of vaporization of ammonia is 23.3 kJ/mol. The molar heat of condensation of ammonia is - 23.3 kJ/mol.
The molar heat of condensation is the opposite of the molar heat of vaporization. The molar heat of vaporization of ammonia is given :
ΔH evaporation = - ΔH condensation
Therefore the molar heat of condensation of ammonia is given by:
ΔH condensation = - 23.3 kJ / mol
That's right. The molar heat of vaporization of ammonia is 23.3 kJ/mol. The molar heat of condesation of ammonia is - 23.3 kJ/mol.
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Molar mass NaOH = 39.997 g/mol
number of moles solute:
n = mass of solute / molar mass
n = 30 / 39.997
n = 0.00075 moles of NaOH
Volume in liters:
500 mL / 1000 => 0.5 L
Therefore :
M = moles of solute / volume ( L )
M = 0.00075 / 0.5
M = 0.0015 mol/L
Given:
N2, volume of 1L of NH3 at STP
Required:
Grams of N2
Solution:
N2 + 3H2 -> 2NH3
Molar mass of N2 = 28g
From the ideal gas equation PV = nRT
n = PV/RT
n = (1 atm)(100 L)/(0.08206 L-atm/mol-K)(273K)
n = 4.46 mol of NH3
from the reaction, we need 2 moles of NH3 to get 1 mole of N2
4.46 mol NH3(1 mol N2/2 mol NH3) = 2.23 moles N2
2.23 moles of N2(28 g N2/1 mol N2) = 62.5g N2
Answer:
It turns blue litmus red
Explanation:
Acids change blue litmus, which is an ink extracted from lichens, to red, and become less acidic when mixed with bases.
