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Mamont248 [21]
3 years ago
8

ou should have observed that Al, Fe, Pb, Sn, and Zn reacted with HCl. List these five metals in order of decreasing reactivity (

most reactive metal first)
Chemistry
1 answer:
AfilCa [17]3 years ago
7 0

Answer:

Al, Zn, Fe, Sn, Pb.

Explanation:

The arrangement can be done using the infomation on electrochemical series of metals.

The electrochemical series is built up by arranging various metals in order of their standard electrode potentials (or reactivity). The most negative E° values are placed at the top of the electrochemical series, and the most positive at the bottom. some of the metals are arranged as follws;  K, Na, Ca, Mg, Al, Zn, Fe, Sn, Pb, H, Cu, Hg, Ag, Au (decreasing reactivity)

One can use the following to remember the arrangement: king Nathan Can Manage All Zone Freely Since Probably He Can Handle All Ages.

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What volume, in milliliters, of a 0.997 M KOH solution is needed to neutralize 30.0 mL of 0.0400 M HCl?
deff fn [24]

Answer:

1.2 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

HCl + KOH —> KCl + H₂O

From the balanced equation,

Mole ratio of the acid, HCl (nₐ) = 1

Mole ratio of base, KOH (n₆) = 1

Finally, we shall determine the volume of the base, KOH needed to neutralize the acid, HCl as follow:

Molarity of base, KOH (M₆) = 0.997 M

Volume of acid, HCl (Vₐ) = 30 mL

Molarity of acid, HCl (Mₐ) = 0.0400 M

Volume of base, KOH (V₆) =?

MₐVₐ / M₆V₆ = nₐ/n₆

0.04 × 30 / 0.997 × V₆ = 1/1

1.2 / 0.997 × V₆ = 1

Cross multiply

0.997 × V₆ = 1.2

Divide both side by 0.997

V₆ = 1.2 / 0.997

V₆ = 1.2 mL

Thus, the volume of the base, KOH needed to neutralize the acid is 1.2 mL.

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