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Mamont248 [21]
3 years ago
8

ou should have observed that Al, Fe, Pb, Sn, and Zn reacted with HCl. List these five metals in order of decreasing reactivity (

most reactive metal first)
Chemistry
1 answer:
AfilCa [17]3 years ago
7 0

Answer:

Al, Zn, Fe, Sn, Pb.

Explanation:

The arrangement can be done using the infomation on electrochemical series of metals.

The electrochemical series is built up by arranging various metals in order of their standard electrode potentials (or reactivity). The most negative E° values are placed at the top of the electrochemical series, and the most positive at the bottom. some of the metals are arranged as follws;  K, Na, Ca, Mg, Al, Zn, Fe, Sn, Pb, H, Cu, Hg, Ag, Au (decreasing reactivity)

One can use the following to remember the arrangement: king Nathan Can Manage All Zone Freely Since Probably He Can Handle All Ages.

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Acetaldehyde and butanoic acid must have the same
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Calculate the volume in liters of a barium acetate solution that contains of barium acetate . Be sure your answer has the correc
Ilya [14]

Answer:

1.09 L

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the volume in liters of a 0.360 mol/L barium acetate solution that contains 100 g of barium acetate. Be sure your answer has the correct number of significant digits.</em>

<em />

The molar mass of barium acetate is 255.43 g/mol. The moles corresponding to 100 grams are:

100 g × (1 mol/255.43 g) = 0.391 mol

0.391 moles of barium acetate are contained in an unknown volume of a 0.360 mol/L barium acetate solution. The volume is:

0.391 mol × (1 L/0.360 mol) = 1.09 L

5 0
3 years ago
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Find the pH. What are the pH values for the following solutions? (a) 0.1 M HCl (b) 0.1 M NaOH (c) 0.05 M HCl (d) 0.05 M NaOH
slega [8]

Answer:

(a) pH=1

(b) pH=1.3

(c) pH=13

(d) pH=12.7

Explanation:

Hello,

In this case, we define the pH in terms of the concentration of hydronium ions as:

pH=-log([H^+])

Which is directly computed for the strong hydrochloric acid (consider a complete dissociation which means the concentration of hydronium equals the concentration of acid) in (a) and (c) as shown below:

(a)

[H^+]=[HCl]=0.1M

pH=-log(0.1)=1

(b)

[H^+]=[HCl]=0.05M

pH=-log(0.05)=1.3

Nevertheless, for the strong sodium hydroxide, we don't directly compute the pH but the pOH since the concentration of base equals the concentration hydroxyl in the solution:

[OH^-]=[NaOH]

pOH=-log([OH^-])

pH=14-pOH

Thus, we have:

(b)

pOH=-log(0.1)=1\\pH=14-1=13

(d)

pOH=-log(0.05)=1.3\\pH=14-1.3=12.7

Best regards.

5 0
3 years ago
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