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shusha [124]
3 years ago
14

If the oh is 6.46(10^-9)M what is the pOH

Chemistry
1 answer:
bagirrra123 [75]3 years ago
3 0

Answer: Thus pOH has value of 8.19

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pOH is calculated by taking negative logarithm of hydroxide  ion concentration.

pOH=-\log [OH^-]

Putting in the values:

pOH=-\log[6.46\times 10^{-9}]

pOH=8.19

Thus pOH has value of 8.19

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Consider the reaction at 500 ° C 500°C . N 2 ( g ) + 3 H 2 ( g ) − ⇀ ↽ − 2 NH 3 ( g ) K c = 0.061 N2(g)+3H2(g)↽−−⇀2NH3(g)Kc=0.06
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Answer:

Q = 0.061 = Kc

Explanation:

Step 1: Data given

Temperature = 500 °C

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1.14 mol/L  N2

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3.42 mol/L NH3

Step 2: Calculate Q

Q=[products]/[reactants]=[NH3]²/ [N2][H2]³

If Qc=Kc then the reaction is at equilibrium.  

If Qc<Kc then the reaction will shift right to reach equilibrium.

If Qc>Kc then the reaction will shift left to reach equilibrium.  

Q = (3.42)² / (1.14 * 5.52³)

Q = 11.6964/191.744

Q = 0.061

Q = Kc the reaction is at equilibrium.  

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