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4 years ago

14

If the oh is 6.46(10^-9)M what is the pOH

1 answer:

bagirrra123 [75]4 years ago

3 0

Answer: Thus pOH has value of 8.19

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pOH is calculated by taking negative logarithm of hydroxide ion concentration.

$pOH=-\log [OH^-]$

Putting in the values:

$pOH=-\log[6.46\times 10^{-9}]$

$pOH=8.19$

Thus pOH has value of 8.19

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2 years ago

During a tug of war competition neither team was able to gain an advantage which of the following explains the force is this sit

natulia [17]

Answer:

b i did the test

Explanation:

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3 years ago

From Young's experiment, how does the frequency of light affect the number of lines observed?

Marina CMI [18]

Answer : (C) "Higher frequencies have larger spaces between lines".

Explanation:

In Young's experiment, the condition for constructive interference is given by :

$dsin\theta=n\lambda$ .........(1)

n is order or number of lines observed

d is distance between slits

$\theta$ is the angle between the path and the line from screen to the slits.

We also know that, $c=\nu \lambda$

or

$\lambda=\dfrac{c}{\nu}$

where,

c is the speed of light

$\nu$ is frequency

$\lambda$ is wavelength

So, equation (1) turns into

$dsin\theta=n\dfrac{c}{\nu}$

$\nu=\dfrac{n\ c}{d\ sin\theta}$

So,

$\nu\propto n$

or

Higher frequencies have larger spaces between line.

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3 0

3 years ago

Read 2 more answers

Who much the velocity of a body when it travels 600m in 5 min

Gwar [14]

Answer:

2 m/s

Explanation:

Applying the formulae of velocity,

V = d/t............. Equation 1

Where V = Velocity of the body, d = distance, t = time

From the question,

Given: d = 600 m, t = 5 minutes = (5×60) = 300 seconds.

Substitute these values into equation 1

V = 600/300

V = 2 m/s.

Hence the velocity of the body when it travels is 2 m/s

3 0

3 years ago

An 80.0-gram sample of water at 10.0°C absorbs 1680 Joules of heat energy. What is the final temperature of the water? a 50.0°C

ICE Princess25 [194]

Answer:

b)15.0°C

Explanation:

Specific Heat of Water=4.2 J/g°C

This means, that 1 g of Water will take 4.2 J of energy to increase its temperature by 1°C.

∴80 g Water will take 80×4.2 J of energy to increase its temperature by 1°C.

80×4.2 J=336 J

Total Energy Provided=1680 J

The temperature increase=\frac{\textrm{Total energy required}}{\textrm{energy required to increase temperature by one degree}}

Temperature increase= $\frac{1680}{336}$

=5°C

Initial Temperature =10°C

Final Temperature=Initial + Increase in Temperature

=10+5=15°C

7 0

3 years ago