Answer:
Polar and bent
Explanation:
It looks like you are trying to find the polarity of H-O-H.
Its Lewis structure is shown in the first diagram below.
It has two lone pairs and two bonding pairs, so it is an AX₂E₂ molecule and its molecular shape is bent, as in the second diagram.
O is much more electronegative than H, so the O-H bond is highly polar. The O atom is at the negative end, and the H atom is at the positive end.
The centre of negative charge is on the O atom, and the centre of negative charge is halfway between the two H atoms, so the molecule has a net dipole pointing "up" in the picture.
Thus, H-O-H has polar bonds and is a polar molecule.
Explanation:
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Answer:
78kJ
Explanation:
Energy change = Energy in (reactants) - Energy out (products)
According to this question, energy is released, meaning that the reaction is EXOTHERMIC. Hence, the energy change will be negative (-) i.e bond energy of reactants is greater than bond energy of products.
Energy in = bond energy of reactants = 43kJ
Energy out = bond energy of products = ?
Energy change of exothermic reaction = -35kJ
Therefore;
-35kJ = 43kJ - x
x = 35kJ + 43kJ
x = 78kJ
The bond energy of the products is 78kJ.
Answer: True
Explanation:
Let's begin by explaining that the vision phenomenon depends on three elements: the observer, the object and the light source.
In addition, objects have pigments, which generally absorb more light than they reflect (they absorb certain wavelengths and reflect others). Therefore, the color that a given object seems to have depends on which parts of the visible electromagnetic spectrum are reflected and which parts are absorbed.
In this sense, the colours we see are in fact the wavelengths that are reflected or transmitted from the object. For example, a red object has that color because when it is illuminated whith white light, the pigments on this object abrsorb all the the wavelengths of the visible electromagnetic spectrum, except red. That is why red light is the only light that is reflected from the mentioned object.