A student performs a reaction that makes aluminum oxide. According to her calculations, she should expect to make 115.2 grams. S
1 answer:
Answer:
The percentage of the student is 58.17%.
Explanation:
Expected yield of aluminum oxide = 115.2 g
Actual yield of aluminum oxide produced =66.9 g
The percentage yield is calculated by dividing actual yield by expected yield and then multiplying it with hundred.
Percentage yield:
The percentage of the student is 58.17%.
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Answer:
A) 1059 J/mol
B) 17,920 J/mol
Explanation:
Given that:
Cp = 29.42 - (2.170*10^-3 ) T + (0.0582*10^-5 ) T2 + (1.305*10^-8 ) T3 – (0.823*10^-11) T4
R (constant) = 8.314
We know that:
We can determine from above if we make
the subject of the formula as:
A).
The formula for calculating change in internal energy is given as:
If we integrate above data into the equation; it implies that:
Hence, the internal energy that must be added to nitrogen in order to increase its temperature from 450 to 500 K = 1059 J/mol.
B).
If we repeat part A for an initial temperature of 273 K and final temperature of 1073 K.
then T = 273 K & T2 = 1073 K
∴